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Date: Wed, 03 Feb 2010 23:21:00 -0000
From: Chris Moller <cmoller@redhat.com>
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To: Tom Tromey <tromey@redhat.com>
CC: Roland McGrath <roland@redhat.com>, Eric Bachalo <ebachalo@redhat.com>,
        Project Archer <archer@sourceware.org>
Subject: Re: PR 11067
References: <4B68A35E.2050301@redhat.com> <m3bpg7yznc.fsf@fleche.redhat.com>	<4B68DC25.1090808@redhat.com> <m3fx5irwx6.fsf@fleche.redhat.com>	<4B69F028.9070006@redhat.com>	<20100203224239.04338AA@magilla.sf.frob.com> <m3wryundfv.fsf@fleche.redhat.com>
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On 02/03/10 17:48, Tom Tromey wrote:
>>>>>> "Roland" == Roland McGrath<roland@redhat.com>  writes:
>>>>>>              
>
> Roland>  I think it should use a format consistent with p/c, e.g.:
> Roland>  (gdb) p 'a'
> Roland>  $1 = 97 'a'
> Roland>  (gdb) p ENUM1
> Roland>  $2 = (enum frobozz) 1 ENUM1
>
> Works for me.  Chris, please do it this way, thanks.
>    

Okay, a whole 5-line patch yields

    (gdb) p e
    $1 = (enum E) 56 Val1
    (gdb) p Val1
    $2 = (enum E) 56 Val1
    (gdb)

(The enum, BTW, is

    num E {
       Val1 = 56,
       Val2
    };

because you can find a 0 any old place.)

Personally, I think

    $2 = (enum E) 56 Val1

is a bit hard to read.  I'd vote for something like

    $2 = (enum E)56 'Val1'

But whatever...


> Tom
>