* questions about objcopy and -O option
@ 2011-02-06 7:25 ali hagigat
2011-02-07 0:17 ` Alan Modra
0 siblings, 1 reply; 2+ messages in thread
From: ali hagigat @ 2011-02-06 7:25 UTC (permalink / raw)
To: binutils
When i use: objcopy -O binary....The man pages of objcopy says:
"When objcopy generates a raw binary file, it will
essentially produce a memory dump of the contents of the input object file. All
symbols and relocation information will be discarded. The memory dump will
start at the load address of the lowest section copied into the output file."
By using objcopy i am creating an output file. So what is memory dump?
Does it create any thing in memory?
What is the content of this file? Only translated instructions, or it
contains some extra reserved bytes? Suppose i had a ld script and set
the start of my sections at 0xffffff00, after using objcopy it seems
that all this information is removed. Is that right?
Does compiler add any extra instructions to my code to remember those
addresses? I mean by looking at the output file of objcopy I can see
the address of 0xffffff00?
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: questions about objcopy and -O option
2011-02-06 7:25 questions about objcopy and -O option ali hagigat
@ 2011-02-07 0:17 ` Alan Modra
0 siblings, 0 replies; 2+ messages in thread
From: Alan Modra @ 2011-02-07 0:17 UTC (permalink / raw)
To: ali hagigat; +Cc: binutils
On Sun, Feb 06, 2011 at 09:07:59AM +0330, ali hagigat wrote:
> What is the content of this file?
If you experiment a little with objcopy you should soon see what
happens.
--
Alan Modra
Australia Development Lab, IBM
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2011-02-07 0:17 ` Alan Modra
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