On 05/24/2017 07:00 AM, Carl Fredrik Forsberg wrote: > I am experiencing problems printing long int values under cygwin64 installed on a Windows 10 machine. > > Below is a test program followed by its output to demonstrate the problem. The program was initially written to demonstrate the output from lrint(), and developed further to demonstrate to myself how negative integers are tackled by printf type specifiers (e.g. %li, %ld etc). Are you compiling with -Wall, or even -Wformat? > > My understanding is that lrint() should return a long int. However I am unable to get printf to print the correct number. Instead its output is treated as an unsigned integer. > Any help or hints would be much appreciated. > > Regards > Carl Fredrik > > #include /* printf */ > #include /* lrint */ > > int main () > { > char text[64]; > printf ( "int -2 = %i\n", -2 ); > printf ( "int -1 = %i\n", -1 ); > printf ( "int 0 = %i\n", 0 ); > printf ( "int 1 = %i\n", 1 ); Okay so far. > printf ( "long int -2 = %li\n", -2 ); > printf ( "long int -1 = %li\n", -1 ); Both buggy. You are passing an int through varargs, but then telling printf to grab a long int. It may or may not work depending on ABI and stack sizes and what not, but gcc will warn you that it is bogus. > printf ( "type cast -1 = %li\n", (long int)-1 ); > printf ( "type cast lrint(-1.0) = %li\n", (long int)lrint(-1.0) ); > printf ( "lrint(-1.0) = %li\n", lrint(-1.0) ); > printf ( "lrint(1.0) = %li\n", lrint(1.0) ); Okay. > printf ( "long int 0 = %li\n", 0 ); > printf ( "long int 1 = %li\n", 1 ); > sprintf( text,"long int -1 = %li", -1 ); Buggy. > printf ( "Via sprintf: %s\n", text); Okay (well, if you overlook the fact that text was populated in a buggy manner) > printf ( "size of long int: %i\n", sizeof(long int)); > printf ( "size of int: %i\n", sizeof(int)); Buggy. size_t should be printed with %zi, not %i (since size_t and int are not necessarily the same type). > return 0; > } > > > compiled by: > gcc lrint_test.c -o lrint_test.exe Missing -Wall. Also, some platforms require the use of -lm to actually link with lrint() (cygwin does not, though). > > Output: > > int -2 = -2 > int -1 = -1 > int 0 = 0 > int 1 = 1 > long int -2 = 4294967294 > long int -1 = 4294967295 Evidence of your bugs. > type cast -1 = -1 > type cast lrint(-1.0) = 4294967295 Now that's an interesting one - it may be that cygwin1.dll actually has buggy behavior in lrint(). In the source code, cygwin/math/lrint.c is dropping down to assembly; it could very well be that the assembly code is incorrectly truncating things at 32 bits (where it is just fine for 32-bit Cygwin, but wrong for 64-bit): long lrint (double x) { long retval = 0L; #if defined(_AMD64_) || defined(__x86_64__) || defined(_X86_) || defined(__i386__) __asm__ __volatile__ ("fistpl %0" : "=m" (retval) : "t" (x) : "st"); #elif defined(__arm__) || defined(_ARM_) retval = __lrint_internal(x); #endif return retval; } But I'm not an assembly coding expert, so perhaps someone else will spot the fix faster. > The confidentiality or integrity of this message can not be guaranteed following transmission on the Internet. Not the worst disclaimer (it is at least not stating something that is unenforceable), but we do prefer that messages on this list be sent without company legalese (even if that means sending from a personal address instead). -- Eric Blake, Principal Software Engineer Red Hat, Inc. +1-919-301-3266 Virtualization: qemu.org | libvirt.org