public inbox for ecos-discuss@sourceware.org
 help / color / mirror / Atom feed
* [ECOS] therad delay problem
@ 2003-11-25  5:36 Aravind B
  2003-11-25  8:30 ` Andrew Lunn
  0 siblings, 1 reply; 3+ messages in thread
From: Aravind B @ 2003-11-25  5:36 UTC (permalink / raw)
  To: ecos-discuss

hi,
	i have written a program which contains  3 thread as  shown.

cyg_user_start(void)
{

printf("entering two threads cyg_user_start() function\n");

cyg_mutex_init(&cliblock);
	cyg_thread_create(3,simple_program,(cyg_addrword_t)2,
	"simple_program_Thread ",(void*) stack[2],4096,
	 &simple_program_Thread,&thread_s[2]);
	cyg_thread_create(4,simple_program1,(cyg_addrword_t)3,
	"simple_program1_Thread",(void*) stack[3],4096,
	 &simple_program1_Thread,&thread_s[3]);
	 cyg_thread_create(5,simple_program2,(cyg_addrword_t)4,
	"simple_program2_Thread",(void*) stack[4],4096,
	 &simple_program2_Thread,&thread_s[4]);

cyg_thread_resume(simple_program_Thread);
cyg_thread_resume(simple_program1_Thread);
cyg_thread_resume(simple_program2_Thread);
}
cyg_alarm_t alarm_Tbcn_func;

void simple_program(cyg_addrword_t data )
{
	int message=(int) data;
	unsigned int i;
	printf("i am thread %d before delay\n",message);

	curr_time=cyg_real_time_clock();
	cyg_clock_to_counter(curr_time,&handle_counterTbcn);
        cyg_alarm_create(handle_counterTbcn, alarm_Tbcn_func,5500,
                	&handle_alarmTbcn, &alarm_Tbcn);
	cyg_alarm_initialize(handle_alarmTbcn,cyg_current_time()+200,0);

		cyg_thread_delay(3);
		while(1)
		{
			if(var==1)
			{
				printf(" hello");
				break;
			}
		}
}

void  simple_program1(cyg_addrword_t data )
{
	int message=(int) data;
	printf("i am thread %d\n",message);
}

void  simple_program2(cyg_addrword_t data )
{
	int message=(int) data;
	printf("i am thread %d\n",message);
	while(1)
	{
	}
}
 void alarm_Tbcn_func( cyg_handle_t alarmTbcn,cyg_addrword_t data)
{
	var=1;
	printf(" i am  in alarm function\n");
}


there is cyg_thread _delay(3) in t1.the control goes to t2 and then
t3.In t3 i have infinite while loop.The control is not going to t1.Is
there any way so that i can signal to t1 that thread delay is over and
it can continue its flow.If so then how it is? 
	
thank u in advance

#############################
Aravind B
Trainee Engineer.
CSIL.


_______________________________________________
This email with any attachments is for the exclusive use of the intended
recipient/s & may contain confidential & legally privileged information.
If you are not the intended recipient pls notify the sender immediately
& delete the email from your system. Any unauthorised use, disclosure,
printing, dissemination, forwarding or copying of this mail is strictly
prohibited and unlawful.
Visit us at : http://www.cranessoftware.com



-- 
Before posting, please read the FAQ: http://sources.redhat.com/fom/ecos
and search the list archive: http://sources.redhat.com/ml/ecos-discuss

^ permalink raw reply	[flat|nested] 3+ messages in thread

* Re: [ECOS] therad delay problem
  2003-11-25  5:36 [ECOS] therad delay problem Aravind B
@ 2003-11-25  8:30 ` Andrew Lunn
  2003-11-25 12:58   ` Gary Thomas
  0 siblings, 1 reply; 3+ messages in thread
From: Andrew Lunn @ 2003-11-25  8:30 UTC (permalink / raw)
  To: Aravind B; +Cc: ecos-discuss

On Tue, Nov 25, 2003 at 10:59:06AM +0530, Aravind B wrote:
> hi,
> 	i have written a program which contains  3 thread as  shown.
> 
> cyg_user_start(void)
> {
> 
> printf("entering two threads cyg_user_start() function\n");
> 
> cyg_mutex_init(&cliblock);
> 	cyg_thread_create(3,simple_program,(cyg_addrword_t)2,
> 	"simple_program_Thread ",(void*) stack[2],4096,
> 	 &simple_program_Thread,&thread_s[2]);
> 	cyg_thread_create(4,simple_program1,(cyg_addrword_t)3,
> 	"simple_program1_Thread",(void*) stack[3],4096,
> 	 &simple_program1_Thread,&thread_s[3]);
> 	 cyg_thread_create(5,simple_program2,(cyg_addrword_t)4,
> 	"simple_program2_Thread",(void*) stack[4],4096,
> 	 &simple_program2_Thread,&thread_s[4]);
> 
> cyg_thread_resume(simple_program_Thread);
> cyg_thread_resume(simple_program1_Thread);
> cyg_thread_resume(simple_program2_Thread);
> }
> cyg_alarm_t alarm_Tbcn_func;
> 
> void simple_program(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	unsigned int i;
> 	printf("i am thread %d before delay\n",message);
> 
> 	curr_time=cyg_real_time_clock();
> 	cyg_clock_to_counter(curr_time,&handle_counterTbcn);
>         cyg_alarm_create(handle_counterTbcn, alarm_Tbcn_func,5500,
>                 	&handle_alarmTbcn, &alarm_Tbcn);
> 	cyg_alarm_initialize(handle_alarmTbcn,cyg_current_time()+200,0);
> 
> 		cyg_thread_delay(3);
> 		while(1)
> 		{
> 			if(var==1)
> 			{
> 				printf(" hello");
> 				break;
> 			}
> 		}
> }
> 
> void  simple_program1(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	printf("i am thread %d\n",message);
> }
> 
> void  simple_program2(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	printf("i am thread %d\n",message);
> 	while(1)
> 	{
> 	}
> }
>  void alarm_Tbcn_func( cyg_handle_t alarmTbcn,cyg_addrword_t data)
> {
> 	var=1;
> 	printf(" i am  in alarm function\n");
> }
> 
> 
> there is cyg_thread _delay(3) in t1.the control goes to t2 and then
> t3.In t3 i have infinite while loop.The control is not going to t1.Is
> there any way so that i can signal to t1 that thread delay is over and
> it can continue its flow.If so then how it is? 

Does the alarm hander get called?

it var a volatile?

   Andrew

-- 
Before posting, please read the FAQ: http://sources.redhat.com/fom/ecos
and search the list archive: http://sources.redhat.com/ml/ecos-discuss

^ permalink raw reply	[flat|nested] 3+ messages in thread

* Re: [ECOS] therad delay problem
  2003-11-25  8:30 ` Andrew Lunn
@ 2003-11-25 12:58   ` Gary Thomas
  0 siblings, 0 replies; 3+ messages in thread
From: Gary Thomas @ 2003-11-25 12:58 UTC (permalink / raw)
  To: Andrew Lunn; +Cc: Aravind B, ecos-discuss

On Tue, 2003-11-25 at 01:30, Andrew Lunn wrote:
> On Tue, Nov 25, 2003 at 10:59:06AM +0530, Aravind B wrote:
> > hi,
> > 	i have written a program which contains  3 thread as  shown.
> > 
> > cyg_user_start(void)
> > {
> > 
> > printf("entering two threads cyg_user_start() function\n");
> > 
> > cyg_mutex_init(&cliblock);
> > 	cyg_thread_create(3,simple_program,(cyg_addrword_t)2,
> > 	"simple_program_Thread ",(void*) stack[2],4096,
> > 	 &simple_program_Thread,&thread_s[2]);
> > 	cyg_thread_create(4,simple_program1,(cyg_addrword_t)3,
> > 	"simple_program1_Thread",(void*) stack[3],4096,
> > 	 &simple_program1_Thread,&thread_s[3]);
> > 	 cyg_thread_create(5,simple_program2,(cyg_addrword_t)4,
> > 	"simple_program2_Thread",(void*) stack[4],4096,
> > 	 &simple_program2_Thread,&thread_s[4]);
> > 
> > cyg_thread_resume(simple_program_Thread);
> > cyg_thread_resume(simple_program1_Thread);
> > cyg_thread_resume(simple_program2_Thread);
> > }
> > cyg_alarm_t alarm_Tbcn_func;
> > 
> > void simple_program(cyg_addrword_t data )
> > {
> > 	int message=(int) data;
> > 	unsigned int i;
> > 	printf("i am thread %d before delay\n",message);
> > 
> > 	curr_time=cyg_real_time_clock();
> > 	cyg_clock_to_counter(curr_time,&handle_counterTbcn);
> >         cyg_alarm_create(handle_counterTbcn, alarm_Tbcn_func,5500,
> >                 	&handle_alarmTbcn, &alarm_Tbcn);
> > 	cyg_alarm_initialize(handle_alarmTbcn,cyg_current_time()+200,0);
> > 
> > 		cyg_thread_delay(3);
> > 		while(1)
> > 		{
> > 			if(var==1)
> > 			{
> > 				printf(" hello");
> > 				break;
> > 			}
> > 		}
> > }
> > 
> > void  simple_program1(cyg_addrword_t data )
> > {
> > 	int message=(int) data;
> > 	printf("i am thread %d\n",message);
> > }
> > 
> > void  simple_program2(cyg_addrword_t data )
> > {
> > 	int message=(int) data;
> > 	printf("i am thread %d\n",message);
> > 	while(1)
> > 	{
> > 	}
> > }
> >  void alarm_Tbcn_func( cyg_handle_t alarmTbcn,cyg_addrword_t data)
> > {
> > 	var=1;
> > 	printf(" i am  in alarm function\n");
> > }
> > 
> > 
> > there is cyg_thread _delay(3) in t1.the control goes to t2 and then
> > t3.In t3 i have infinite while loop.The control is not going to t1.Is
> > there any way so that i can signal to t1 that thread delay is over and
> > it can continue its flow.If so then how it is? 
> 
> Does the alarm hander get called?
> 
> it var a volatile?

Does your program include <cyg/kernel/kapi.h>
See: http://ecos.sourceware.org/fom-serv/ecos/cache/94.html

-- 
Gary Thomas <gary@mlbassoc.com>
MLB Associates


-- 
Before posting, please read the FAQ: http://sources.redhat.com/fom/ecos
and search the list archive: http://sources.redhat.com/ml/ecos-discuss

^ permalink raw reply	[flat|nested] 3+ messages in thread

end of thread, other threads:[~2003-11-25 12:58 UTC | newest]

Thread overview: 3+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2003-11-25  5:36 [ECOS] therad delay problem Aravind B
2003-11-25  8:30 ` Andrew Lunn
2003-11-25 12:58   ` Gary Thomas

This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for read-only IMAP folder(s) and NNTP newsgroup(s).