From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 20697 invoked by alias); 17 Oct 2007 15:00:06 -0000 Received: (qmail 20649 invoked by uid 22791); 17 Oct 2007 15:00:05 -0000 X-Spam-Status: No, hits=-2.5 required=5.0 tests=AWL,BAYES_00,DK_POLICY_SIGNSOME,SPF_HELO_PASS,SPF_PASS X-Spam-Check-By: sourceware.org Received: from mx1.redhat.com (HELO mx1.redhat.com) (66.187.233.31) by sourceware.org (qpsmtpd/0.31) with ESMTP; Wed, 17 Oct 2007 15:00:01 +0000 Received: from int-mx1.corp.redhat.com (int-mx1.corp.redhat.com [172.16.52.254]) by mx1.redhat.com (8.13.8/8.13.1) with ESMTP id l9HExwNv000726 for ; Wed, 17 Oct 2007 10:59:59 -0400 Received: from pobox.corp.redhat.com (pobox.corp.redhat.com [10.11.255.20]) by int-mx1.corp.redhat.com (8.13.1/8.13.1) with ESMTP id l9HExv1w028185; Wed, 17 Oct 2007 10:59:57 -0400 Received: from [127.0.0.1] (sebastian-int.corp.redhat.com [172.16.52.221]) by pobox.corp.redhat.com (8.13.1/8.13.1) with ESMTP id l9HExpDE018683; Wed, 17 Oct 2007 10:59:54 -0400 Message-ID: <47162305.9040102@redhat.com> Date: Wed, 17 Oct 2007 15:00:00 -0000 From: Andrew Cagney User-Agent: Thunderbird 1.5.0.12 (X11/20070530) MIME-Version: 1.0 To: Phil Muldoon CC: Frysk Hackers Subject: Re: getType().getSize() safe/correct way to determine Register size? References: <47160A0A.3010406@redhat.com> In-Reply-To: <47160A0A.3010406@redhat.com> Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-IsSubscribed: yes Mailing-List: contact frysk-help@sourceware.org; run by ezmlm Precedence: bulk List-Id: List-Subscribe: List-Post: List-Help: , Sender: frysk-owner@sourceware.org X-SW-Source: 2007-q4/txt/msg00063.txt.bz2 Phil Muldoon wrote: > As the subject says, but pedantically: > > int registerSize = IA32Registers.EAX.getType().getSize(); > byte[] byteOrderedRegister = new byte[registerSize]; > task.access(IA32Registers.EAX, 0, registerSize, > byteOrderedRegister, 0, false); > > Is this a safe/correct way to determine register size? Yes. > > > If not, any other way? > > Regards > > Phil