[Bug c++/12823] New: Cannot call member function template of nested class inside template class

[Bug c++/12823] New: Cannot call member function template of nested class inside template class

[bsamwel at xs4all dot nl]

PLEASE REPLY TO gcc-bugzilla@gcc.gnu.org ONLY, *NOT* gcc-bugs@gcc.gnu.org.

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=12823

           Summary: Cannot call member function template of nested class
                    inside template class
           Product: gcc
           Version: 3.3.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: bsamwel at xs4all dot nl
                CC: gcc-bugs at gcc dot gnu dot org
  GCC host triplet: i686-pc-linux-gnu

AFAICS the following code should compile.


template<int a>
struct foo
{
  struct barney
  {
    template<int c>
    void bar()
    {  
    }
  };

  void baz()
  {
    barney b;
    b.bar<0>(); // (This is line 15.)
  }
};

Comeau's online compiler compiles this snippet just fine. GCC 3.3.2 gives me:

gcc test.cc
test.cc: In member function `void foo<a>::baz()':
test.cc:15: error: parse error before `;' token

[Bug c++/12823] Cannot call member function template of nested class inside template class

[bangerth at dealii dot org]

PLEASE REPLY TO gcc-bugzilla@gcc.gnu.org ONLY, *NOT* gcc-bugs@gcc.gnu.org.

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=12823


bangerth at dealii dot org changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |INVALID


------- Additional Comments From bangerth at dealii dot org  2003-10-29 14:43 -------
No, this is invalid code. The type of b is template dependent, so
you need to use the following syntax (which does compile with
gcc):
    b.template bar<0>(); // (This is line 15.)

W.