[Bug c++/13542] New: the overload of < operator doesn't work for complex<double> when use stl sort

[Bug c++/13542] New: the overload of < operator doesn't work for complex<double> when use stl sort

[tjiq at 21cn dot com]

the code following doesn't compile:

typedef complex<double> Tp;
vector<Tp> vp;
int operator<(const Tp &a, const Tp &b)
{
 return a.imag()<b.imag();
}

sort(vp.begin(),vp.end());

-- 
           Summary: the overload of < operator doesn't work for
                    complex<double> when use stl sort
           Product: gcc
           Version: 3.3.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: tjiq at 21cn dot com
                CC: gcc-bugs at gcc dot gnu dot org


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=13542

[Bug libstdc++/13542] the overload of < operator doesn't work for complex<double> when use stl sort

[pinskia at gcc dot gnu dot org]

------- Additional Comments From pinskia at gcc dot gnu dot org  2004-01-02 05:07 -------
Your op< is in the global namespace, but at the place where
    it is used (inside std::sort), only
    operators in namespace std are looked up because both operands
    are in namespace std. There are several other instances
    of this bug/feature in the database.
    
    You can work around the problem by putting the op< into
    namespace std.

-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
          Component|c++                         |libstdc++
         Resolution|                            |INVALID


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=13542

[Bug libstdc++/13542] the overload of < operator doesn't work for complex<double> when use stl sort

[pinskia at physics dot uc dot edu]

------- Additional Comments From pinskia at physics dot uc dot edu  2004-01-02 06:44 -------
Subject: Re:  the overload of < operator doesn't work for complex<double> when use stl sort


On Jan 2, 2004, at 01:37, Jiqing Tang wrote:

> Thx a lot, it solves my problem,
>
> I just wonder if I use BCC32, it doesn't require me to declare the < 
> operator in the std namespace, does that conform to the
> standard?

no, then BCC32 does not conform to the standard.

Thanks,
Andrew Pinski



-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=13542