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* [Bug fortran/30487] New: Math implicit function in forall statement causes compiler error
@ 2007-01-16 20:33 icksa1 at gmail dot com
2007-01-16 21:30 ` [Bug fortran/30487] " burnus at gcc dot gnu dot org
2007-01-17 1:37 ` kargl at gcc dot gnu dot org
0 siblings, 2 replies; 3+ messages in thread
From: icksa1 at gmail dot com @ 2007-01-16 20:33 UTC (permalink / raw)
To: gcc-bugs
Hi:
I noticed that whenever I use a math function (such as sqrt, cos, log) in a
forall all statement that further uses of that function caused gfortran to say
that the function has no implicit type. I've shown an example program below:
program test
implicit none
integer :: i
real :: a, c(5) = (/1.0,2.0,3.0,4.0,5.0/), d(5)
a = sqrt(2.0)
d(:) = 0.0
forall (i = 1:5, sqrt(c(i)) < 2.0)
d(i) = i
end forall
end program test
If I try to compile the above program I get the following error:
In file test.f90:8
a = sqrt(2.0)
1
Error: Symbol 'sqrt' at (1) has no IMPLICIT type
If I comment out the line "a = sqrt(2.0)", everything works fine. Also, if I
don't use the sqrt test in the forall statement, everything works fine. If you
substitute other mathematical functions for sqrt (such as log or cos) it fails
to compile in a similar way.
I tried this in the latest experimental build (downloaded from the gfortran
wiki) and had similar problems.
Thank You
--
Summary: Math implicit function in forall statement causes
compiler error
Product: gcc
Version: 4.1.2
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: fortran
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: icksa1 at gmail dot com
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=30487
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2007-01-16 20:33 [Bug fortran/30487] New: Math implicit function in forall statement causes compiler error icksa1 at gmail dot com
2007-01-16 21:30 ` [Bug fortran/30487] " burnus at gcc dot gnu dot org
2007-01-17 1:37 ` kargl at gcc dot gnu dot org
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