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From: "pinskia at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
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Subject: [Bug c++/102937] Miscompilation with -O3 and aliasing of char* and
 size_t
Date: Mon, 25 Oct 2021 21:52:41 +0000
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D102937

Andrew Pinski <pinskia at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
         Resolution|FIXED                       |INVALID

--- Comment #4 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
(In reply to David Rohr from comment #3)
> thanks, makes me feel pretty stupid...
> I thought it is not a problem since char* may alias, but apparently size_=
t*
> may not alias char**... if I understood correctly...

No, you are still misunderstand aliasing rules.

Basically you can access any type via a character type.
That is:
char *a =3D (char*)t;
a[n] =3D ...;
access *t

since you are doing basically:
char *a;
size_t *t =3D (size_t)&a;
*t =3D ....
access a

size_t only alias size_t and the signed version of what the type size_t was
typedef of (size_t is unsigned).
In the above case, you access "char*" as size_t which is undefined.  if you
instead accessed it as char rather than size_t then the code would be well
defined.
That is:
char *a;
char *b =3D (char*)&a;
b[0] =3D ...
b[1] =3D ...
b[2] =3D ...
....
access a

There are other ways fixing the issue by using memcpy (or an union but an u=
nion
in this case is harder to use correctly) than extra assignments.=