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From: "jvdelisle at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug fortran/105473] semicolon allowed when list-directed read
 integer with decimal='point'
Date: Sat, 14 May 2022 22:00:09 +0000
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D105473

--- Comment #7 from Jerry DeLisle <jvdelisle at gcc dot gnu.org> ---
My apologies for taking some time to get back to this.  After a closer look=
, I
realize that in the original test case there is no problem.  The semicolon =
is
an acceptable value separator regardless of decimal=3D'point' or decimal=3D=
'comma'

Take these two examples:

1) The comma is the decimal keeper so semicolon must be used as the separat=
or

  implicit none
  integer n,m,ios
  real r
  character(20):: testinput =3D '1;17;3,14159'
  n =3D 999
  print *,'testinput =3D "',testinput,'"'
  read(testinput,*,decimal=3D'comma', iostat=3Dios) n, m, r
  print *,'n=3D',n,' m=3D ', m,' r=3D ', r,' ios=3D',ios
  if(ios>0) print *,'testinput was not an integer'
end program

2) The point is the decimal keeper so semicolon may be used as the separato=
r or
a comma

  implicit none
  integer n,m,ios
  real r
  character(20):: testinput =3D '1;17;3.14159'
  n =3D 999
  print *,'testinput =3D "',testinput,'"'
  read(testinput,*,decimal=3D'point', iostat=3Dios) n, m, r
  print *,'n=3D',n,' m=3D ', m,' r=3D ', r,' ios=3D',ios
  if(ios>0) print *,'testinput was not an integer'
end program

In the original test case, the semicolon is a separator and is simply ending
the read as no value is there.=