[Bug middle-end/106578] New: spurious -Wuse-after-free=2 after conditional free()

["gcc.gnu.org at aydos dot de" <gcc-bugzilla@gcc.gnu.org>]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=106578

            Bug ID: 106578
           Summary: spurious -Wuse-after-free=2 after conditional free()
           Product: gcc
           Version: 12.1.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: middle-end
          Assignee: unassigned at gcc dot gnu.org
          Reporter: gcc.gnu.org at aydos dot de
  Target Milestone: ---

I am new to GCC's components, so feel free to rename the headers if I
classified the bug wrong.

The following code throws the `use-after-free` error:

```
#include <stdlib.h>

void *buf = NULL;
size_t buf_size = 0;

int main() {
    void *tmp = buf;

    buf = realloc(tmp, 10);

    // Realloc returns a pointer to the new object, or a null pointer if the
    // new object could not be allocated. Free the original pointer
    // to avoid memory leak in latter case.
    if (!buf)
        free(tmp);
}
```
```
$ gcc -Wall -Wuse-after-free=2 main.c
main.c: In function ‘main’:
main.c:15:17: warning: pointer ‘tmp’ may be used after ‘realloc’
[-Wuse-after-free]
   15 |                 free(tmp);
      |                 ^~~~~~~~~
main.c:9:15: note: call to ‘realloc’ here
    9 |         buf = realloc(tmp, 10);
      |               ^~~~~~~~~~~~~~~~
```

A workaround is to `realloc` directly `buf` and use `tmp` for the return value
of `realloc`:

```
#include <stdlib.h>

void *buf = NULL;
size_t buf_size = 0;

int main() {
    void *tmp = buf;

    tmp = realloc(buf, 10);

    if (!tmp)
        free(buf);
}
```

>From what I saw in other bugs this one may also be related to the meta-bug
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104075.

Can someone confirm this case?