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From: "redi at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug libstdc++/107015] New: __debug::bitset has different ABI for
 -std=c++98
Date: Fri, 23 Sep 2022 11:26:05 +0000
X-Bugzilla-Reason: CC
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X-Bugzilla-Product: gcc
X-Bugzilla-Component: libstdc++
X-Bugzilla-Version: 12.2.1
X-Bugzilla-Keywords: ABI
X-Bugzilla-Severity: normal
X-Bugzilla-Who: redi at gcc dot gnu.org
X-Bugzilla-Status: UNCONFIRMED
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X-Bugzilla-Priority: P3
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D107015

            Bug ID: 107015
           Summary: __debug::bitset has different ABI for -std=3Dc++98
           Product: gcc
           Version: 12.2.1
            Status: UNCONFIRMED
          Keywords: ABI
          Severity: normal
          Priority: P3
         Component: libstdc++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: redi at gcc dot gnu.org
  Target Milestone: ---

g:17e3f4aa17624af245bae5408b6e5c1fdf90c9ec and the
g:c5589aa7e1e8bf1e56d3c46d952675e1087be311 follow-up changed <debug/bitset>=
 to
not use the debug base container in C++11 mode, because that non-literal ba=
se
class means that __debug::bitset is non-literal too.

But that means that __debug::bitset is not ABI compatible between -std=3Dc+=
+98
and later modes.

We should either remove the _Safe_sequence_base class unconditionally (and =
at
that point, we might as well just get rid of <debug/bitset> and make it an
alias for the normal one), or we should use the base unconditionally and gi=
ve
up the literal class property.

The standard doesn't actually require is_literal_v<bitset<N>> to be true,
although maybe it should.=