From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: by sourceware.org (Postfix, from userid 48) id 261323858C52; Sat, 4 Feb 2023 12:17:29 +0000 (GMT) DKIM-Filter: OpenDKIM Filter v2.11.0 sourceware.org 261323858C52 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gcc.gnu.org; s=default; t=1675513049; bh=PFQLhNYIxpEhDh4Ob2uNFESzu7sv3MVUFb6JWBJDXb8=; h=From:To:Subject:Date:In-Reply-To:References:From; b=NsUZ8zF+i5C3Z1950SNNjgLAOUyGi2gqovHrNCdxykNa3E+vm/DpvmFwcNiMMthGD xlubErKJ6QpX3V20YQiRCoaC8IYmgBbU6OGolnAlNHgGQcwdaYuSwhm/zK+GKN23/G qARvDeaMG/fDFP/mHv8RpfJv4hV68DEGHOPhdIyU= From: "dcb314 at hotmail dot com" To: gcc-bugs@gcc.gnu.org Subject: [Bug middle-end/108657] csmith: possible wrong checksum with -O3 and -ftrivial-auto-var-init=zero Date: Sat, 04 Feb 2023 12:17:29 +0000 X-Bugzilla-Reason: CC X-Bugzilla-Type: changed X-Bugzilla-Watch-Reason: None X-Bugzilla-Product: gcc X-Bugzilla-Component: middle-end X-Bugzilla-Version: 13.0 X-Bugzilla-Keywords: wrong-code X-Bugzilla-Severity: normal X-Bugzilla-Who: dcb314 at hotmail dot com X-Bugzilla-Status: UNCONFIRMED X-Bugzilla-Resolution: X-Bugzilla-Priority: P3 X-Bugzilla-Assigned-To: unassigned at gcc dot gnu.org X-Bugzilla-Target-Milestone: --- X-Bugzilla-Flags: X-Bugzilla-Changed-Fields: Message-ID: In-Reply-To: References: Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Bugzilla-URL: http://gcc.gnu.org/bugzilla/ Auto-Submitted: auto-generated MIME-Version: 1.0 List-Id: https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D108657 --- Comment #6 from David Binderman --- (In reply to David Binderman from comment #5) > (In reply to David Binderman from comment #0) > > Also, the possible bug seems to have first occurred sometime before 202= 30103 >=20 > Also before 20221201: And before 20221101: $ /home/dcb36/gcc/results.20221101/bin/gcc -w -O3 -ftrivial-auto-var-init= =3Dzero bug880.c $ ./a.out checksum =3D BCC02729 $ /home/dcb36/gcc/results.20221101/bin/gcc -v 2>&1 | fgrep exp gcc version 13.0.0 20221101 (experimental) (4acc4c2be84d6607)=20 $=