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From: "gene at staubsaal dot de" <gcc-bugzilla@gcc.gnu.org> To: gcc-bugs@gcc.gnu.org Subject: [Bug c++/115180] New: [regression] free-nonheap-object on std::vector usage Date: Tue, 21 May 2024 18:11:47 +0000 [thread overview] Message-ID: <bug-115180-4@http.gcc.gnu.org/bugzilla/> (raw) https://gcc.gnu.org/bugzilla/show_bug.cgi?id=115180 Bug ID: 115180 Summary: [regression] free-nonheap-object on std::vector usage Product: gcc Version: 14.1.1 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c++ Assignee: unassigned at gcc dot gnu.org Reporter: gene at staubsaal dot de Target Milestone: --- Compiler: gcc (GCC) 14.1.1 Compile flags: -std=c++20 -O3 -Wfree-nonheap-object The following code produces an "-Wfree-nonheap-object" warning, which doesn't happen with '-O2' or using an older version of gcc. This seems to be a false warning. (Or maybe even some false optimization going on?) ``` #include <cassert> #include <vector> // Since K+1 the returned vector has size() >= 1 inline auto f(size_t N, size_t K) { return std::vector<std::vector<size_t>>(K+1, std::vector<size_t>(N, 0)); } // create another vector, but derive size from the previous vector inline auto g(std::vector<std::vector<size_t>> const& v1) { size_t const K = v1.size() - 1; size_t const N = v1[0].size(); return std::vector<std::vector<size_t>>(K+1, std::vector<size_t>(N, 0)); } struct S { std::vector<size_t> v1; std::vector<size_t> v2; // v1, v2always have the same length }; auto h(size_t N, size_t K) { assert(N>0); assert(N >= K); auto v1 = f(N, K); auto v2 = g(v1); auto ss = std::vector<S>{}; for (size_t i{0}; i < v1.size(); ++i) { ss.emplace_back(S{v1[i], {}}); } for (auto& s : ss) { s.v1.back() += 1; } return ss; } auto all = h(4, 3); ``` For convenience a link to godbolt: https://godbolt.org/z/dPj1YYf7x
next reply other threads:[~2024-05-21 18:11 UTC|newest] Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top 2024-05-21 18:11 gene at staubsaal dot de [this message] 2024-05-21 18:15 ` [Bug c++/115180] " gene at staubsaal dot de
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