From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: by sourceware.org (Postfix, from userid 48) id EA92F3954473; Tue, 10 Mar 2020 03:20:57 +0000 (GMT) DKIM-Filter: OpenDKIM Filter v2.11.0 sourceware.org EA92F3954473 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gcc.gnu.org; s=default; t=1583810457; bh=13L3qWCjI2u/rtS+Z5JAuODMArA+bYlYr9CrrMZbgaM=; h=From:To:Subject:Date:In-Reply-To:References:From; b=pEXSzSwp64pSVc1yh3ol9PhUu6UIDTWZnao7Sz+tfytX6yDV0Zb2oXUvJQUO8xEId 8dDO9izEe9u70m8Py/u/xHwRYDxplaTthyRneEO4lJmx6NFmnZXp2vvQ6+oYtOCF0e foc3NRriawKZBAwxt8cM5ita7zJ+I98FDH/uQgQ8= From: "pinskia at gcc dot gnu.org" To: gcc-bugs@gcc.gnu.org Subject: [Bug inline-asm/31386] wrong registers used in cmov instruction Date: Tue, 10 Mar 2020 03:20:57 +0000 X-Bugzilla-Reason: CC X-Bugzilla-Type: changed X-Bugzilla-Watch-Reason: None X-Bugzilla-Product: gcc X-Bugzilla-Component: inline-asm X-Bugzilla-Version: 4.3.0 X-Bugzilla-Keywords: X-Bugzilla-Severity: minor X-Bugzilla-Who: pinskia at gcc dot gnu.org X-Bugzilla-Status: RESOLVED X-Bugzilla-Resolution: INVALID X-Bugzilla-Priority: P3 X-Bugzilla-Assigned-To: unassigned at gcc dot gnu.org X-Bugzilla-Target-Milestone: --- X-Bugzilla-Flags: X-Bugzilla-Changed-Fields: bug_status resolution Message-ID: In-Reply-To: References: Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Bugzilla-URL: http://gcc.gnu.org/bugzilla/ Auto-Submitted: auto-generated MIME-Version: 1.0 X-BeenThere: gcc-bugs@gcc.gnu.org X-Mailman-Version: 2.1.29 Precedence: list List-Id: Gcc-bugs mailing list List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Tue, 10 Mar 2020 03:20:58 -0000 https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D31386 Andrew Pinski changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution|--- |INVALID --- Comment #4 from Andrew Pinski --- Invalid as mentioned, you need the early clobbers, otherwise GCC thinks the output and input registers can be the same. In this case the output regist= ers which is held in operand 0 has to be different from operands 4 and 5.=