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Date: Thu, 19 Feb 2009 15:20:00 -0000
Subject: [Bug libstdc++/39243]  New: Invalid thousands separator in russian locale
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From: "Sergey dot Belyashov at gmail dot com" <gcc-bugzilla@gcc.gnu.org>
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I create this simple program:

#include <iostream>
#include <locale>
#include <clocale>
#include <cstdio>

using namespace std;

int main()
{
    locale loc("ru_RU.UTF-8");
    cout.imbue(loc);
    cout << 1234.56 << std::endl;

    setlocale(LC_NUMERIC, "ru_RU.UTF-8");
    printf("%'.2f\n", 1234.56);

    return 0;
}


Result is:
1?234,56: (in hex): \x31\xC2\x32\x33\x34\x2C\x35\x36 
1 234,56: (in hex): \x31\x20\x32\x33\x34\x2C\x35\x36 
Here '?' is invalid symbol \xC2

then I try (code in C):
#include <stdio.h>
#include <locale.h>
int main() {
   setlocale(LC_ALL, "ru_RU.UTF-8");
   printf("\"%s\"\n", localeconv()->thousands_sep);
   printf("%f\n", 1234.56);
   return 0;
}

Output is: " " (one space in double quotes)


-- 
           Summary: Invalid thousands separator in russian locale
           Product: gcc
           Version: 4.3.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: libstdc++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: Sergey dot Belyashov at gmail dot com
 GCC build triplet: i486-linux-gnu
  GCC host triplet: i486-linux-gnu
GCC target triplet: i486-linux-gnu


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=39243