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From: "redi at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug c++/47294] New: definition of function template can be explicitly-qualified with a namespace it isn't a member of
Date: Fri, 14 Jan 2011 15:48:00 -0000	[thread overview]
Message-ID: <bug-47294-4@http.gcc.gnu.org/bugzilla/> (raw)

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=47294

           Summary: definition of function template can be
                    explicitly-qualified with a namespace it isn't a
                    member of
           Product: gcc
           Version: 4.6.0
            Status: UNCONFIRMED
          Keywords: accepts-invalid
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: redi@gcc.gnu.org


namespace N
{
    void f();
}

template<typename T>
void N::f(T)   // ERROR does not match any declaration in N
{
}

int main()
{
    ::f(0);
}

This is forbidden by [namespace.memdef]p2 but g++ accepts it without error.

EDG, Clang and Sun reject it.


If there isn't an (incompatible) overload of N::f then g++ rejects it.


             reply	other threads:[~2011-01-14 15:44 UTC|newest]

Thread overview: 4+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2011-01-14 15:48 redi at gcc dot gnu.org [this message]
2011-01-14 16:05 ` [Bug c++/47294] " redi at gcc dot gnu.org
2012-01-05 23:54 ` pinskia at gcc dot gnu.org
2021-08-09 20:21 ` pinskia at gcc dot gnu.org

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