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* [Bug go/49889] New: Calling a function whose name is obscured by a local variable does not produce an error
@ 2011-07-28 18:36 rluble at gmail dot com
  2011-08-04  4:08 ` [Bug go/49889] " ian at gcc dot gnu.org
  2011-08-04  4:10 ` ian at airs dot com
  0 siblings, 2 replies; 3+ messages in thread
From: rluble at gmail dot com @ 2011-07-28 18:36 UTC (permalink / raw)
  To: gcc-bugs

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49889

           Summary: Calling a function whose name is obscured by a local
                    variable does not produce an error
           Product: gcc
           Version: 4.7.0
            Status: UNCONFIRMED
          Severity: minor
          Priority: P3
         Component: go
        AssignedTo: ian@airs.com
        ReportedBy: rluble@gmail.com


Created attachment 24859
  --> http://gcc.gnu.org/bugzilla/attachment.cgi?id=24859
Small program exhibiting the mentioned error

When calling a function whose name is obscured by a local variable on a *tuple
assignment* statement (as in the example below) no error is produced and the
generated code does not have the function call. 


func test(a int) (int, int) {
  b:=a+1
  return b,a
}

func main() {
    test, a := 1, 1
    c,d := 1,1

    c,d = test(a)
}


The expected behaviour is to produce an error.


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2011-07-28 18:36 [Bug go/49889] New: Calling a function whose name is obscured by a local variable does not produce an error rluble at gmail dot com
2011-08-04  4:08 ` [Bug go/49889] " ian at gcc dot gnu.org
2011-08-04  4:10 ` ian at airs dot com

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