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* [Bug go/49889] New: Calling a function whose name is obscured by a local variable does not produce an error
@ 2011-07-28 18:36 rluble at gmail dot com
2011-08-04 4:08 ` [Bug go/49889] " ian at gcc dot gnu.org
2011-08-04 4:10 ` ian at airs dot com
0 siblings, 2 replies; 3+ messages in thread
From: rluble at gmail dot com @ 2011-07-28 18:36 UTC (permalink / raw)
To: gcc-bugs
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49889
Summary: Calling a function whose name is obscured by a local
variable does not produce an error
Product: gcc
Version: 4.7.0
Status: UNCONFIRMED
Severity: minor
Priority: P3
Component: go
AssignedTo: ian@airs.com
ReportedBy: rluble@gmail.com
Created attachment 24859
--> http://gcc.gnu.org/bugzilla/attachment.cgi?id=24859
Small program exhibiting the mentioned error
When calling a function whose name is obscured by a local variable on a *tuple
assignment* statement (as in the example below) no error is produced and the
generated code does not have the function call.
func test(a int) (int, int) {
b:=a+1
return b,a
}
func main() {
test, a := 1, 1
c,d := 1,1
c,d = test(a)
}
The expected behaviour is to produce an error.
^ permalink raw reply [flat|nested] 3+ messages in thread
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2011-07-28 18:36 [Bug go/49889] New: Calling a function whose name is obscured by a local variable does not produce an error rluble at gmail dot com
2011-08-04 4:08 ` [Bug go/49889] " ian at gcc dot gnu.org
2011-08-04 4:10 ` ian at airs dot com
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