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From: "jakub at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org> To: gcc-bugs@gcc.gnu.org Subject: [Bug middle-end/52056] Code optimization sensitive to trivial changes Date: Tue, 31 Jan 2012 01:04:00 -0000 [thread overview] Message-ID: <bug-52056-4-av5VVhLoQf@http.gcc.gnu.org/bugzilla/> (raw) In-Reply-To: <bug-52056-4@http.gcc.gnu.org/bugzilla/> http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52056 Jakub Jelinek <jakub at gcc dot gnu.org> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |irar at gcc dot gnu.org, | |jakub at gcc dot gnu.org --- Comment #2 from Jakub Jelinek <jakub at gcc dot gnu.org> 2012-01-30 23:16:03 UTC --- The signed vs. unsigned long right shift is quite significant, because Intel chips don't support signed quadword right shifts, only unsigned quadword right shifts (and left shifts), except that AMD chips with -mxop do support that. So, with the unsigned long right shift the loop is vectorized, while with signed long right shift it is not, and clearly in this case the vectorization (at least two elements at a time) isn't beneficial, but the cost model doesn't figure that out. So the faster times are without vectorization, you can get the same speed with -O3 -fno-tree-vectorize even with the unsigned shift. Even AVX can't process more than two elements at a time, only AVX2 will be able, how fast is that loop on AVX2 capable chips compared to non-vectorized remains to be seen.
next prev parent reply other threads:[~2012-01-30 23:17 UTC|newest] Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top 2012-01-30 20:02 [Bug c/52056] New: " gccbug at jamasaru dot com 2012-01-30 23:17 ` [Bug c/52056] " gccbug at jamasaru dot com 2012-01-31 1:04 ` jakub at gcc dot gnu.org [this message] 2012-01-31 11:40 ` [Bug tree-optimization/52056] Vectorizer cost model is imprecise rguenth at gcc dot gnu.org 2012-07-13 8:52 ` rguenth at gcc dot gnu.org
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