[Bug c++/52374] New: [C++11] Fails to transform id-expression into dependent base member access in lambda expression

["ai.azuma at gmail dot com" <gcc-bugzilla@gcc.gnu.org>]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52374

             Bug #: 52374
           Summary: [C++11] Fails to transform id-expression into
                    dependent base member access in lambda expression
    Classification: Unclassified
           Product: gcc
           Version: 4.7.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: ai.azuma@gmail.com


Created attachment 26742
  --> http://gcc.gnu.org/bugzilla/attachment.cgi?id=26742
Output of -v option and preprocessed file

In the lambda expression's compound statement, id-expressions referring to
non-static members should be transformed into class member access expressions
by prefixing `(*this).'. However, GCC fails the transformation when
id-expressions involved are qualified-ids and refer to dependent base members.

A test case is as follows;

////////////////////////////////////////////////////////////////////
struct B
{
  int get() const { return 42; }
};

template<typename X>
struct D
  : public X
{
  int get() const { return [this]() -> int { return X::get(); }(); }
};

int main()
{
  D<B> d;
  d.get();
}

////////////////////////////////////////////////////////////////////

For the above mentioned well-formed code, 4.7.0 20120218 (experimental) with
-std=c++11 complains as follows;

main.cpp: In instantiation of 'D<X>::get() const [with X = B]::<lambda()>':
main.cpp:10:29:   required from 'struct D<X>::get() const [with X =
B]::<lambda()>'
main.cpp:10:65:   required from 'int D<X>::get() const [with X = B]'
main.cpp:16:9:   required from here
main.cpp:10:60: error: cannot call member function 'int B::get() const' without
object

`X::get' in the lambda expression should be implicitly transformed into
`(*this).X::get', and the test case should compile successfully.