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From: "holger.hopp at sap dot com" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug regression/52973] New: visibility attribute for class is not passed to its members
Date: Fri, 13 Apr 2012 12:36:00 -0000
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52973

             Bug #: 52973
           Summary: visibility attribute for class is not passed to its
                    members
    Classification: Unclassified
           Product: gcc
           Version: 4.7.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: regression
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: holger.hopp@sap.com


In following code, gcc-4.7 does not accept the visibility attribute
defined in the class declaration:

template <class T> class __attribute__((visibility("default"))) a
{
public:
  /* A */ static int c;
};

class __attribute__((visibility("default"))) b : a <b> {};

template<> /* B */ int a<b>::c = 0;


With g++-4.7, a<b>::c is hidden, with g++-4.6 (and before) it is not.

$ g++-4.7 -fvisibility=hidden -c def.cpp && objdump -Ct def.o | grep "a<b>"
0000000000000000 g     O .bss    0000000000000004 .hidden a<b>::c

$ g++-4.6 -fvisibility=hidden -c def.cpp && objdump -Ct def.o | grep "a<b>"
0000000000000000 g     O .bss    0000000000000004 a<b>::c

Setting the default visibility at /* A */ or /* B */ works with
g++-4.7, but I think that it still should work also with the code above.