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From: "pinskia at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug middle-end/54571] Missed optimization converting between bit sets
Date: Tue, 06 Jul 2021 08:39:30 +0000	[thread overview]
Message-ID: <bug-54571-4-QIb6o84FHY@http.gcc.gnu.org/bugzilla/> (raw)
In-Reply-To: <bug-54571-4@http.gcc.gnu.org/bugzilla/>

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=54571

--- Comment #2 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
(In reply to Richard Biener from comment #1)
> Confirmed.  The natural place to optimize this is the tree level phiopt pass.
> 
>   <bb 2>:
>   _3 = x_2(D) & 2;
>   if (_3 != 0)
>     goto <bb 3>;
>   else
>     goto <bb 4>;
> 
>   <bb 3>:
>   y_5 = y_4(D) | 1;
> 
>   <bb 4>:
>   # y_1 = PHI <y_4(D)(2), y_5(3)>
> 
> where we should handle
> 
> int f1(int x, int y, int d) { int tem; if ((tem = x & d)) y |= tem; return
> y; }
> 
> as well.  Yes, that's just y |= x & d, but it falls out naturally if the
> transform is implemented in a generic enough way.


This one should be easy to add to match.pd:

(simplify
 (cond @1 (ior @2 INTEGER_CST@3) @2)
 (ior @2 (bit_and (negate (convert @1)) @3)))


(bit_and (negate (convert thurth_value@1)) integer_onep)
should be just converted to:
@1
Which is not done right now, I fill that as a bug.

  parent reply	other threads:[~2021-07-06  8:39 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2012-09-13 21:25 [Bug middle-end/54571] New: " rth at gcc dot gnu.org
2012-09-13 21:25 ` [Bug middle-end/54571] " rth at gcc dot gnu.org
2012-09-14  8:40 ` rguenth at gcc dot gnu.org
2021-07-06  8:39 ` pinskia at gcc dot gnu.org [this message]
2021-07-20  3:16 ` pinskia at gcc dot gnu.org
2021-11-15  0:52 ` pinskia at gcc dot gnu.org
2023-06-07 15:20 ` pinskia at gcc dot gnu.org

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