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From: "ashish.sadanandan at gmail dot com" <gcc-bugzilla@gcc.gnu.org>
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Subject: [Bug c++/54849] New: Override specifier with trailing return type
Date: Sun, 07 Oct 2012 17:42:00 -0000
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54849

             Bug #: 54849
           Summary: Override specifier with trailing return type
    Classification: Unclassified
           Product: gcc
           Version: 4.7.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: ashish.sadanandan@gmail.com


struct Base
{
  virtual auto f () const -> int = 0;
};

struct Derived : public Base
{
  virtual auto f () const -> int override { return 0; }
};

int main() { Derived d; }

The above fails to compile. Errors:

error: expected ';' at end of member declaration
error: 'override' does not name a type

Both errors are reported for the definition of Derived::f. According to the
standard, section 8.4.1 Function definitions have the form

function-definition:
attribute-specifier-seqopt decl-specifier-seqopt declarator
virt-specifier-seqopt function-body

The declarator in a function-definition shall have the form
  D1 ( parameter-declaration-clause ) cv-qualifier-seqopt
    ref-qualifieropt exception-specificationopt attribute-specifier-seqopt
trailing-return-typeopt

Since the declarator includes the trailing return type, I believe the above
should compile.

If the override specifier is moved before the -> the code does compile, but
that doesn't jive with the standard.