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From: "redi at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
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Subject: [Bug c++/54948] template unnecessarily displayed as "A<
 template-parameter-1-1 >" not "A<T>"
Date: Tue, 18 Jan 2022 13:24:12 +0000
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D54948

Jonathan Wakely <redi at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
           See Also|                            |https://gcc.gnu.org/bugzill
                   |                            |a/show_bug.cgi?id=3D104094

--- Comment #5 from Jonathan Wakely <redi at gcc dot gnu.org> ---
This continues to be annoying. Libstdc++ has loads of forward declarations =
of
templates, e.g. in <type_traits>:

  // Forward declarations
  template<typename>
    struct is_reference;
  template<typename>
    struct is_function;
  template<typename>
    struct is_void;
  template<typename>
    struct remove_cv;
  template<typename>
    struct is_const;

Which means we then get diagnostics containing:

std::is_same<_U1, typename std::remove_cv< <template-parameter-1-1> >::type=
&>

I agree with Manu that this could just show "typename" here. We don't refer=
 to
the template-parameter-1-1 type again in the diagnostic, so why do we care
about uniquely identifying it as 1-1?

But why is it even using the name from the remove_cv declaration? That shou=
ld
not be appearing in the *use* of remove_cv here. I've filed that as PR 1040=
94.=