[Bug c++/55189] enable -Wreturn-type by default

["redi at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55189

Jonathan Wakely <redi at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
           Keywords|                            |diagnostic
             Status|UNCONFIRMED                 |NEW
   Last reconfirmed|                            |2012-11-03
            Summary|g++ compiler does not       |enable -Wreturn-type by
                   |report missing return on    |default
                   |function with return type   |
     Ever Confirmed|0                           |1

--- Comment #3 from Jonathan Wakely <redi at gcc dot gnu.org> 2012-11-03 13:03:14 UTC ---
(In reply to comment #2)
> If this is not bug why shouldn't we make
> 
> int n;
> n =;
> printf("%d",n);
> 
> to be legal code, compiler should simply assign whatever it wants. Right ?

No, because that's not even legal syntax, so that's a completely different
case.


> -Wreturn-type should be set by default.

OK, so let's change the report to say that then.

In general though, please don't report bugs claiming there are no warnings if
you haven't even tried -Wall, there's a notice when you report a bug asking you
to check that.

Reduced example:

struct A { int i; };

A f()
{
  A a = { 0 };
  // missing return
}

int main()
{
  A a = f();
  return a.i;
}