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From: "meanarbez at gmail dot com" <gcc-bugzilla@gcc.gnu.org>
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Subject: [Bug c++/55189] New: g++ compiler does not report missing return on function with return type
Date: Sat, 03 Nov 2012 10:30:00 -0000
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55189

             Bug #: 55189
           Summary: g++ compiler does not report missing return on
                    function with return type
    Classification: Unclassified
           Product: gcc
           Version: 4.6.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: meanarbez@gmail.com


Compiled with MinGW port of g++, compiles without errors or warnings:

g++ bug.cpp -o bug.exe

Minimal sample bug.cpp:

        #include <iostream>

        using namespace std;


        class Example
        {
          protected:

            int m_x;

          public:

            Example()
            {
              m_x = 0;
            }

            Example( const Example &ref )
            { 
              m_x = ref.m_x;
            }

            ~Example()
            {
            }

            int get()
            { 
              return m_x;
            }

            void set( int x )
            { 
              m_x = x;
            }

            Example &operator =( Example ref )
            {
              m_x = ref.m_x;
              return *this;
            }
        };


        Example func( Example p )
        {
          Example m;

          m.set( p.get() );

          // ! COMPILER DOES NOT DETECT ABSENCE OF FUNCTION RETURN !
        }


        int main()
        {
          Example m;

          m.set( 7 );

          Example k;

          k = func( m );

          // ! CONSEQUENTLY RESULT IS RANDOM !

          cout << k.get() << endl;

          return 0;
        }