[Bug c++/61806] New: [C++11] Expression sfinae w/o access gives hard error in partial template specializations

[Bug c++/61806] New: [C++11] Expression sfinae w/o access gives hard error in partial template specializations

[daniel.kruegler at googlemail dot com]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61806

            Bug ID: 61806
           Summary: [C++11] Expression sfinae w/o access gives hard error
                    in partial template specializations
           Product: gcc
           Version: 4.10.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: daniel.kruegler at googlemail dot com

The following code, compiled with gcc 4.10.0 20140714 (experimental) using the
flags

-Wall -Wextra -std=c++11 -pedantic

or - alternatively -

-Wall -Wextra -std=c++1y -pedantic

//-----------------------
struct true_type 
{
  static const bool value = true;
};

struct false_type 
{
  static const bool value = false;
};

template<class T>
T&& declval();

template<typename> struct check { typedef void type; };

template<typename T, typename Enable = void>
struct has_public_f : false_type {};

template<typename T>
struct has_public_f<
    T,
    typename check<
        decltype(
            declval<T&>().f()
        )
    >::type
> : true_type {};

struct Spub  { public: void f(); };
struct Spriv { private: void f(); };

static_assert( has_public_f<Spub>::value, "Ouch");
static_assert(!has_public_f<Spriv>::value, "Ouch");

int main() {}
//-----------------------

is rejected with the following diagnostics:

<quote>
prog.cc: In instantiation of 'struct has_public_f<Spriv>': 
prog.cc:33:35: required from here 
prog.cc:30:30: error: 'void Spriv::f()' is private 
  struct Spriv { private: void f(); }; 
                               ^ 
prog.cc:27:15: error: within this context 
  > : true_type {}; 
                ^ 
prog.cc:30:30: error: 'void Spriv::f()' is private 
  struct Spriv { private: void f(); }; 
                               ^ 
prog.cc:27:15: error: within this context 
  > : true_type {}; 
                ^ 
prog.cc:30:30: error: 'void Spriv::f()' is private 
  struct Spriv { private: void f(); }; 
                               ^ 
prog.cc:33:16: error: within this context     
  static_assert(!has_public_f<Spriv>::value, "Ouch"); 
                 ^ 
prog.cc:33:1: error: static assertion failed: Ouch 
  static_assert(!has_public_f<Spriv>::value, "Ouch"); 
  ^
</quote>

It seems that in this context there is no silent rejection of the partial
specialization, albeit it should.

[Bug c++/61806] [C++11] Expression sfinae w/o access gives hard error in partial template specializations

[ville.voutilainen at gmail dot com]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61806

Ville Voutilainen <ville.voutilainen at gmail dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |NEW
   Last reconfirmed|                            |2014-12-14
                 CC|                            |ville.voutilainen at gmail dot com
     Ever confirmed|0                           |1
      Known to fail|4.10.0                      |5.0

--- Comment #1 from Ville Voutilainen <ville.voutilainen at gmail dot com> ---
Clang accepts the code.

[Bug c++/61806] [C++11] Expression sfinae w/o access gives hard error in partial template specializations

[ppalka at gcc dot gnu.org]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61806

--- Comment #9 from Patrick Palka <ppalka at gcc dot gnu.org> ---
*** Bug 80475 has been marked as a duplicate of this bug. ***