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From: "andysem at mail dot ru" <gcc-bugzilla@gcc.gnu.org> To: gcc-bugs@gcc.gnu.org Subject: [Bug c++/88165] error: default member initializer for 'A::B::m' required before the end of its enclosing class Date: Fri, 22 Apr 2022 10:29:22 +0000 [thread overview] Message-ID: <bug-88165-4-QDNi2scqEN@http.gcc.gnu.org/bugzilla/> (raw) In-Reply-To: <bug-88165-4@http.gcc.gnu.org/bugzilla/> https://gcc.gnu.org/bugzilla/show_bug.cgi?id=88165 --- Comment #13 from andysem at mail dot ru --- (In reply to Jonathan Wakely from comment #10) > (In reply to Fedor Chelnokov from comment #7) > > This struct definition: > > ``` > > struct A { > > struct B { > > int i = 0; > > B() {} > > This declares default constructor, meaning that the type is default > constructible. Period. > > By declaring B(); you assert that B is default constructible. > > > }; > > A(B = {}); > > This is valid, because the user-provided default constructor for B is all > the compiler needs to see to know that B={} is valid. > > > }; > > ``` > > is accepted by GCC, but another one ({} replaced with = default) is not: > > ``` > > struct C { > > struct D { > > int i = 0; > > D() = default; > > This declares a default constructor that might be defined implicitly by the > compiler, **or** it might get deleted if the member definitions of D would > make the implicit default constructor ill-formed. This is obviously very > different from the case where you declare B(); There is no assertion that D > is default constructible, the compiler has to deduce whether or not that's > true. That depends on the default member initializer for D::i. The > initializer (which is just '0' here) is a "complete class context" which > means it is not processed until the class D is complete (this allows you to > use other members, or e.g. sizeof(D) as the initializer). > > A nested class like C::D is not complete until its enclosing class is > complete. This means the initializer for C::D::i is compiled after C is > complete. This means whether C::D is default constructible is not known > until C is complete. > > > > }; > > C(D = {}); > > This requires checking whether C::D is default constructible, but we are > still in the body of C, so C is not complete, which means C::D is not > complete, which means we don't know if C::D is default constructible. Does it? I thought the default arguments were only evaluated at the point where they are actually used, i.e. in this case - when `C` constructor is invoked with no arguments. > > }; > > ``` > > Demo: https://gcc.godbolt.org/z/WTPdTn1Yf > > > > Could you please explain why? I though that both must be same accepted or > > same rejected. > > I hope the explanation above helps. Thank you for the explanation. If this is how the standard specifies compiler behavior, I wonder if this should be considered as a defect (DR). There is nothing in `std::numeric_limits<double>::max()` that depends on the definition of `C`, so there is no reason to prevent it from compiling.
next prev parent reply other threads:[~2022-04-22 10:29 UTC|newest] Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top [not found] <bug-88165-4@http.gcc.gnu.org/bugzilla/> 2021-12-14 5:07 ` pinskia at gcc dot gnu.org 2021-12-14 5:16 ` pinskia at gcc dot gnu.org 2022-01-13 6:55 ` fchelnokov at gmail dot com 2022-04-22 8:18 ` jcl at nvidia dot com 2022-04-22 8:26 ` redi at gcc dot gnu.org 2022-04-22 8:35 ` redi at gcc dot gnu.org 2022-04-22 8:44 ` fchelnokov at gmail dot com 2022-04-22 8:55 ` jcl at nvidia dot com 2022-04-22 10:29 ` andysem at mail dot ru [this message] 2022-04-22 10:42 ` redi at gcc dot gnu.org
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