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From: "jason at gcc dot gnu.org" <gcc-bugzilla@gcc.gnu.org>
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Subject: [Bug c++/91618] [9/10/11/12 Regression] template-id required to
 friend a function template, even for a qualified-id
Date: Thu, 07 Apr 2022 15:59:39 +0000
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D91618

Jason Merrill <jason at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |jason at gcc dot gnu.org

--- Comment #11 from Jason Merrill <jason at gcc dot gnu.org> ---
Interesting, seems that G++ never implemented that bullet.  Even though we
allowed the friend declaration, it didn't match the template:

template <class T> int f(T t) { return t.i; }

class A {
  friend int ::f(A);
  int i;
};

int main()
{
  f(A()); // link error, trying to call non-template function=20=20=20=20=
=20=20=20=20=20=20=20=20=20=20=20=20=20=20=20
}

I also notice that the bullet in question is gone in the C++23 draft, repla=
ced
by new wording in [dcl.meaning.general]:

(2.2.1.3) =E2=80=94 each remaining function template is replaced with the
specialization chosen by deduction from the friend declaration (13.10.3.7) =
or
discarded if deduction fails.

So, it's not clear to me that this really counts as a regression.=