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From: "stefansf at linux dot ibm.com" <gcc-bugzilla@gcc.gnu.org>
To: gcc-bugs@gcc.gnu.org
Subject: [Bug sanitizer/99814] New: regexec fails with -fsanitize=address
Date: Mon, 29 Mar 2021 09:44:02 +0000
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https://gcc.gnu.org/bugzilla/show_bug.cgi?id=3D99814

            Bug ID: 99814
           Summary: regexec fails with -fsanitize=3Daddress
           Product: gcc
           Version: 11.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: sanitizer
          Assignee: unassigned at gcc dot gnu.org
          Reporter: stefansf at linux dot ibm.com
                CC: dodji at gcc dot gnu.org, dvyukov at gcc dot gnu.org,
                    jakub at gcc dot gnu.org, kcc at gcc dot gnu.org, marxi=
n at gcc dot gnu.org
  Target Milestone: ---
            Target: s390x

Testing against today's commit

https://gcc.gnu.org/g:d579e2e76f9469e1b386d693af57c5c4f0ede410

on s390x we have:

$ gcc pr98920.c -fsanitize=3Daddress && ./a.out
failed to match

The testcase succeeds without `-fsanitize=3Daddress`.

In GDB I see that the address loaded from _ZN14__interception12real_regexecE
equals the address of regexec@GLIBC_2.2 which explains why the testcase fai=
ls.=20
Without `-fsanitize=3Daddress` function regexec@@GLIBC_2.3.4 is executed.=