Pass by reference problem

Pass by reference problem

[e211]

//The following code works and there is no way it should.  Seems like a bug
someone put in on purpose

#include <iostream>
using namespace std;

void swap(int *x, int *y)
{
	int temp;
	temp = *x;
	*x = *y;
	*y = temp;
}

int main()
{
	int x = 10;
	int y = 20;
	cout << x << " " << y << endl;
	swap(x,y);  //how does this work, there is no way this should compile and
run and actually work
	cout << x << " " << y << endl;
}

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Re: Pass by reference problem

[Andrew Pinski]

On Mon, Feb 16, 2009 at 7:29 PM, e211 <e211@hotmail.com> wrote:
>
> //The following code works and there is no way it should.  Seems like a bug
> someone put in on purpose
>
> #include <iostream>
> using namespace std;
>
> void swap(int *x, int *y)
> {
>        int temp;
>        temp = *x;
>        *x = *y;
>        *y = temp;
> }
>
> int main()
> {
>        int x = 10;
>        int y = 20;
>        cout << x << " " << y << endl;
>        swap(x,y);  //how does this work, there is no way this should compile and
> run and actually work
>        cout << x << " " << y << endl;
> }

iostream is bringing in the definition of std::swap which takes a
reference.  And you have a "using namespace std;" there.

Thanks,
Andrew Pinski