From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 16527 invoked by alias); 6 Jun 2005 12:53:23 -0000 Mailing-List: contact gcc-help-help@gcc.gnu.org; run by ezmlm Precedence: bulk List-Archive: List-Post: List-Help: Sender: gcc-help-owner@gcc.gnu.org Received: (qmail 16501 invoked by uid 22791); 6 Jun 2005 12:53:17 -0000 Received: from smtp6.infineon.com (HELO smtp6.infineon.com) (217.10.50.128) by sourceware.org (qpsmtpd/0.30-dev) with ESMTP; Mon, 06 Jun 2005 12:53:17 +0000 Received: from unknown (HELO mucse211.eu.infineon.com) (172.29.27.228) by smtp6.infineon.com with ESMTP; 06 Jun 2005 14:53:14 +0200 X-SBRS: None Received: from mucse212.eu.infineon.com ([172.29.27.230]) by mucse211.eu.infineon.com over TLS secured channel with Microsoft SMTPSVC(5.0.2195.6713); Mon, 6 Jun 2005 14:53:13 +0200 Received: from blrse201.ap.infineon.com ([172.20.20.12]) by mucse212.eu.infineon.com over TLS secured channel with Microsoft SMTPSVC(5.0.2195.6713); Mon, 6 Jun 2005 14:53:12 +0200 content-class: urn:content-classes:message MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Subject: Inline assembly Date: Mon, 06 Jun 2005 12:53:00 -0000 Message-ID: <04EE7AD0450F7B498BA216312943A1A11D9EA1@blrse201.ap.infineon.com> From: To: X-SW-Source: 2005-06/txt/msg00040.txt.bz2 Hi, This kind of inline assembly is given in the GCC Test suits asm ("" : "=3Dr" (tmp) : "0" (tmp)); As per my understanding the input and output remains in the same register.But there is no instruction in the first double coats(""). The Question is=20 What will be the value of r(tmp) after this instruction.Whether it is equivalent to ld r2,#0x0 Thanks in advance, Chris