How to pass function names as parameter?

How to pass function names as parameter?

[Walter Kasberg]

I want to pass function names as parameter to a subroutine.
I made a simple test programm:
-------------------
/* */
#include <stdio.h>


main ()
{
 int feins ();
 int fzwei ();
 int rufen ();
  
  rufen ( feins () );

  rufen ( fzwei () );
}

rufen ( der )
int (*der) ();
{
   (*der) ();
}

feins () 
{
  printf ("\nThat is module eins\n\n");
}

fzwei ()
{
  printf ("\nThat is module zwei\n\n");
}
---------------------
The program compiles and links successfully.
But running the program gives an error. the first call 'rufen( feins () )' 
calls the
correct function 'feins' and the message there. But then I get 'message access 
error'
(as I would translate it).
 
What could be wrong?

Any hint is appreciated.

Walter

Re: How to pass function names as parameter?

[John Love-Jensen]

Hi Walter,

This isn't doing what you think it is doing:

 rufen ( feins () );
 rufen ( fzwei () );

You probably wanted:

 rufen ( feins );
 rufen ( fzwei );

HTH,
--Eljay

Re: How to pass function names as parameter?

[Walter Kasberg]

On Wednesday 28 February 2007 19:48, John Love-Jensen wrote:
> Hi Walter,
>
> This isn't doing what you think it is doing:
>
>  rufen ( feins () );
>  rufen ( fzwei () );
>
> You probably wanted:
>
>  rufen ( feins );
>  rufen ( fzwei );
>
> HTH,
> --Eljay
I tried it, but it too does not work. There is still the memory address error.

Walter

Re: How to pass function names as parameter?

[Walter Kasberg]

On Wednesday 28 February 2007 19:48, John Love-Jensen wrote:
> Hi Walter,
>
> This isn't doing what you think it is doing:
>
>  rufen ( feins () );
>  rufen ( fzwei () );
>
> You probably wanted:
>
>  rufen ( feins );
>  rufen ( fzwei );
>
> HTH,
> --Eljay
sorry, discard my previous mail.
I made a mistake: I changed the code but did not save the changes and compiled 
the old version.
Thanks, you are right, now it works.

Walter