Re: How do I avoid this warning?

[Gokhan Kisacikoglu <kisa@centropolisfx.com>]

Dave Williss wrote:
> 
> I get a lot of warnings of the type:
> 
>     warning: choosing `FOO::operator BAR*()` over `FOO::operator const
> BAR*()
>         for conversion from FRED to const BAR*
>         because conversion sequence for the argument is better
> 

Who is FRED? I guess you meant FOO! ;)

* Anyway, I guess the following would work better;

FOO::operator BAR*()			// non-const cases
FOO::operator const BAR*() const 	// for const cases

This will always use BAR * if FOO is not const, and const BAR * whenever
FOO is const. This is at least more consistent...

* If you need to do explicitely convert to const BAR * from a non-const
FOO, then maybe you should have an explicit method for that;

const BAR * FOO::asBAR() const

FOO *f = new FOO;
const BAR *constb = f->asBar();
BAR *b = f;	// guaranteed to return BAR * in this context

BTW, if your destructors are properly defined as virtual, then deleting
a BAR * should never be a problem...

HTH,
Gokhan