* Use of pointer to protected member function won't compile in 3.4.4
@ 2005-07-12 21:47 Paul Dubuc
2005-07-12 21:51 ` corey taylor
0 siblings, 1 reply; 2+ messages in thread
From: Paul Dubuc @ 2005-07-12 21:47 UTC (permalink / raw)
To: gcc-help
This code will compile with g++ 3.3.4, but 3.4.4 gives me the following error:
Test.cc: In member function `const char* Derived::getCharge() const':
Test.cc:18: error: `char* Base::makeCharge_(const char*) const' is protected
Test.cc:31: error: within this context
Why can't the Derived class use a pointer to it's Base class' protected member
function? Is this a bug in 3.4.4, or is this no longer allowed?
Help!
Here's the code:
class Base {
protected:
const char * getAttr_(unsigned char type,
char * (Base::*pf)(const char *) const) const;
char * makeCharge_(const char *) const;
};
const char * Base::getAttr_(unsigned char type,
char * (Base::*pf)(const char *) const) const
{
return 0;
}
char * Base::makeCharge_(const char * ptr) const
{
return 0;
}
class Derived : public Base {
public:
const char * getCharge() const;
};
const char * Derived::getCharge() const
{
return(getAttr_(0, &Base::makeCharge_));
}
--
Paul M. Dubuc
"It is not enough to do your best; you must know what to do, and THEN do your
best." -- W. Edwards Deming
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: Use of pointer to protected member function won't compile in 3.4.4
2005-07-12 21:47 Use of pointer to protected member function won't compile in 3.4.4 Paul Dubuc
@ 2005-07-12 21:51 ` corey taylor
0 siblings, 0 replies; 2+ messages in thread
From: corey taylor @ 2005-07-12 21:51 UTC (permalink / raw)
To: Paul Dubuc; +Cc: gcc-help
This has been changed since 3.4.0 and is noted in the last bullet of
the C++ changes:
http://gcc.gnu.org/gcc-3.4/changes.html
corey
On 7/12/05, Paul Dubuc <pdubuc@cas.org> wrote:
> This code will compile with g++ 3.3.4, but 3.4.4 gives me the following error:
>
> Test.cc: In member function `const char* Derived::getCharge() const':
> Test.cc:18: error: `char* Base::makeCharge_(const char*) const' is protected
> Test.cc:31: error: within this context
>
> Why can't the Derived class use a pointer to it's Base class' protected member
> function? Is this a bug in 3.4.4, or is this no longer allowed?
>
> Help!
>
> Here's the code:
>
> class Base {
>
> protected:
>
> const char * getAttr_(unsigned char type,
> char * (Base::*pf)(const char *) const) const;
>
> char * makeCharge_(const char *) const;
> };
>
> const char * Base::getAttr_(unsigned char type,
> char * (Base::*pf)(const char *) const) const
> {
> return 0;
> }
>
> char * Base::makeCharge_(const char * ptr) const
> {
> return 0;
> }
>
> class Derived : public Base {
>
> public:
>
> const char * getCharge() const;
> };
>
> const char * Derived::getCharge() const
> {
> return(getAttr_(0, &Base::makeCharge_));
> }
>
>
> --
> Paul M. Dubuc
>
> "It is not enough to do your best; you must know what to do, and THEN do your
> best." -- W. Edwards Deming
>
^ permalink raw reply [flat|nested] 2+ messages in thread
end of thread, other threads:[~2005-07-12 21:51 UTC | newest]
Thread overview: 2+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2005-07-12 21:47 Use of pointer to protected member function won't compile in 3.4.4 Paul Dubuc
2005-07-12 21:51 ` corey taylor
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for read-only IMAP folder(s) and NNTP newsgroup(s).