Reza Roboubi skrev:
> Hi,
> 
> this is the test file:
> 
> $ cat test.c
> #define x "llll
> #define y "
> char * c =3D x y ;
> 
> Now, if I do this:
> $ gcc -Wall -E test.c
> It works as expected, and produces preprocessed output that is
> perfectly compilable.
> 
> But, if I do this:
> $ gcc -Wall -c test.c -o test.o
> Then I get this:
> test.c:3: error: missing terminating " character
> test.c:3: error: missing terminating " character
> test.c:3: error: expected expression before =91;=92 token
> 
> The questions are:
> a.)  What's even going on here?  Why the apparent inconsistency?
> b.)  What _should_ be the correct behavior, both in terms of the
> (extended) GNU C language, and also the standard C language?
> 
> Thanks so much for your help.
> 
> Reza.
> 

I believe that each c-style string must be encapsulated with " even for 
the preprocessor to work. Actually, at least gcc-4.3 emits warnings 
about missing termination for both line 1 and 2 in your test case.

Perhaps you could work something out with the ## concatenation operator?
-- 


//*David Sveningsson [eXt]*

Freelance coder | Game Development Student
http://sidvind.com

Thou shalt make thy program's purpose and structure clear to thy fellow 
man by using the One True Brace Style, even if thou likest it not, for 
thy creativity is better used in solving problems than in creating 
beautiful new impediments to understanding.