From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: from xry111.site (xry111.site [IPv6:2001:470:683e::1]) by sourceware.org (Postfix) with ESMTPS id E3A9F3858D39 for ; Tue, 7 Mar 2023 05:20:36 +0000 (GMT) DMARC-Filter: OpenDMARC Filter v1.4.2 sourceware.org E3A9F3858D39 Authentication-Results: sourceware.org; dmarc=pass (p=reject dis=none) header.from=xry111.site Authentication-Results: sourceware.org; spf=pass smtp.mailfrom=xry111.site DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/simple; d=xry111.site; s=default; t=1678166434; bh=oA064leTZLh3/5ZzAMgkdlmjYYXhwvP1mpu6vD9Hg7I=; h=Subject:From:To:Cc:Date:In-Reply-To:References:From; b=NkguR0qnQYnSzmXxY8JhOfa2TD4sKNz7o7JM/Ph6sgL+ydXiCwBjv7nUon/WWkOBU h9UluvMIJam1R8ZVZJX/th8lvbnMncZRE0UxLpsDx14UFjIM79OFTSxEgCwPS16q5p bKqcFYreJ3GIbkzVuyRG1NCHSQ8Ow6dgkntrepoY= Received: from localhost.localdomain (xry111.site [IPv6:2001:470:683e::1]) (using TLSv1.3 with cipher TLS_AES_256_GCM_SHA384 (256/256 bits) key-exchange ECDHE (P-256) server-signature ECDSA (P-384) server-digest SHA384) (Client did not present a certificate) (Authenticated sender: xry111@xry111.site) by xry111.site (Postfix) with ESMTPSA id 2C13A65EB6; Tue, 7 Mar 2023 00:20:33 -0500 (EST) Message-ID: <8214a50e7b25e9392c75bfb5a83a46e86b9216c2.camel@xry111.site> Subject: Re: [NEED HELP][GCOV] uncoverage virtual destructor From: Xi Ruoyao To: Nhu Vo , Jonathan Wakely Cc: gcc-help , Chan Le , Vu Phan , Viet Ngo , Duc La , Duy Pham , Dinh Thanh Truc , Sy Nguyen Duc Date: Tue, 07 Mar 2023 13:20:31 +0800 In-Reply-To: References: Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable User-Agent: Evolution 3.46.4 MIME-Version: 1.0 X-Spam-Status: No, score=-1.8 required=5.0 tests=BAYES_00,DKIM_SIGNED,DKIM_VALID,DKIM_VALID_AU,DKIM_VALID_EF,LIKELY_SPAM_FROM,SPF_HELO_PASS,SPF_PASS,TXREP autolearn=no autolearn_force=no version=3.4.6 X-Spam-Checker-Version: SpamAssassin 3.4.6 (2021-04-09) on server2.sourceware.org List-Id: On Tue, 2023-03-07 at 05:18 +0000, Nhu Vo wrote: > According to your explanation about D0, D1, D2, we have some questions > as follows: > =C2=A0 > 1. We understood that D0 will call D1, D1 will call D2, is it correct? > (as image below) It's implementation defined, D0 can either call D1 or inline D1 (i. e. perform the action of D1 itself). --=20 Xi Ruoyao School of Aerospace Science and Technology, Xidian University