Re: Problem with the string

["kanishk rastogi" <kanishk.85@gmail.com>]

On 11/24/06, Andrew Haley <aph@redhat.com> wrote:
> kanishk rastogi writes:
>  > On 11/24/06, Andrew Haley <aph@redhat.com> wrote:
>  > > kanishk rastogi writes:
>  > >  > On 11/24/06, Andrew Haley <aph@redhat.com> wrote:
>  > >  > > kanishk rastogi writes:
>  > >  > >  > if i call a func like:
>  > >  > >  >
>  > >  > >  > func("kanishk");
>  > >  > >  > the string "kanishk" will be defined in readonly segment or in read -
>  > >  > >  > write segment ?
>  > >  > >  > if they will be in read-only segment i dont want that....
>  > >  > >  > how can this be done
>  > >  > >
>  > >  > > Dammit, how many times do I have to repeat this?
>  > >  > >
>  > >  > > You just gotta declare them right.  Like this:
>  > >  > >
>  > >  > > char s[] = "kanishk";
>  > >  > > func(s);
>  > >
>  > >  > thanks for the advice andrew
>  > >  > and sorry for the annoyance
>  > >  > but the fact is I cant change the code because its more than 8000
>  > >  > lines so i am asking for a feature in gcc which i would have missed
>  > >
>  > > Your code is wrong.  "How do I get gcc to compile this code with these
>  > > bugs?" is not a sensible question.  Fix the bugs!
>
>  > sorry
>  > the code is not buggy. i think u have misunderstood the real problem statement.
>  >
>  > so the problem in more detail is as below:
>  >
>  > printf("kanishk");
>  >
>  > the above code compiles perfectly with gcc -Wall.
>  > gcc by default puts the string into read execute segment,but i want to
>  > put string "kanishk" into writeable memory (or other than read execute
>  > segment). Is there a way for doing this without making any change in
>  > calling sequence (for example it may be regulated by some switch in
>  > gcc) or there is no provision in C99 standard for it.
>
> OK, if it's not a bug, I need to ask another question.  I don't
> understand you at all: why do you want to put a constant string into
> writable memory?    Is this embedded, or what?

its not.

>
> Andrew.
>
i