Hello,
With <iostream> int8_t prints out char according to ascii number. Similarly
it reads a single char, which cannot be static converted. The compiler
gives no warning whatsoever. But when <cstdio> is used with scanf %hhd and
printf %d it works perfectly. Is this really the intended <iostream>
functioning? In Rust i8 and C <stdio.h> int8 works fine, too.
#include <iostream>
#include <cstdint>

int main()
{
std::int8_t myInt{65};
myInt += 1;
std::cout << myInt;
}

Guess what this returns?
Character "B".

int main()
{
std::int8_t myInt{};
std::cin >> myInt;
std::cout << myInt;
}
This will also read a character, and
print the characters ascii value.
So if I give it 3, it read it as '3', and prints out 51.


The compiler gives no warning of this whatsoever with the flags:
                "-std=c++20",
                "-pedantic-errors",
                "-Wall",
                "-Wpedantic",
                "-Wshadow",
                "-Wcast-align",
                "-Wlogical-op",
                "-Wno-unused-parameter",
                "-Weffc++",
                "-Wextra",
                "-Wconversion",
                "-Wsign-conversion".


It does seem like a mistake to have `signed char` and `unsigned char`
display as characters rather than numbers, since `char` is a distinct type.
And so `char` could display as a character and the other two as integers.

Wish you can change this, or at least have a warning, because <iostream>
functions fine for higher bitted integers.

Thanks.
OE