Re: Pointer to a function forbid!!

[Sebastian Huber <sebastian-huber@web.de>]

Hello,
you take the pointer of the A::f() function, this functions calls then your 
member function via the handed over this pointer. This approach works only if 
the code that calls the funktion via the pointer passes an arbitrary object 
via a void pointer to the function, in our special case the this pointer.
The declaration of such functions is should be similar to void* (*f)(void*), 
at least for a function executed in a POSIX thread. I don't know if your 
handler functions works the same way. If not you have to use a globel object 
and a wraper function.

On Friday 12 April 2002 19:18, you wrote:
> Thank you, but could you explain something to me ?  Is f the name of the
> function I'm needing a pointer to, or is it ADDED to the class?  I'm not
> quite sure how I use this.  Is m() the member function that I'm needing
> the pointer to? I know I replace the A with the name of my class, but
> I'm not sure which other items I'm supposed to substitute for.  Thanks a
> lot man.
>
> > -----Original Message-----
> > From: sebastian-huber@web.de [mailto:sebastian-huber@web.de]
> > Sent: Friday, April 12, 2002 11:59 AM
> > To: Glover George
> > Subject: Re: Pointer to a function forbid!!
> >
> >
> > Hello,
> > if you want to avoid global variables, you can try this:
> >
> > class A {
> > public:
> > 	static void f( void* thisPointer)
> > 	{
> > 		static_cast<A*>( thisPointer)->m();
> > 	}
> >
> > private:
> > 	void m();
> > };
> >
> > This works a least with the POSIX thread functions.
> >
> > [...]