How do I deprecate a class?

How do I deprecate a class?

[Thimo.Neubauer]

Hi!

I'd like to mark a class as deprecated, i.e. any instantiation or method
call should be warned. After reading

http://gcc.gnu.org/onlinedocs/gcc-4.1.2/gcc/Type-Attributes.html#Type-Attributes

I concluded that

  class Foo {
  public:
	void  bar(int x);
  } __attribute__ ((deprecated));

should do the trick. However

  int main() {
	Foo f;

	return 0;
  };

only warns about the (obviously) unused variable but nothing else:

beachboys++ /tmp> make
g++ -Wall    foo.cc   -o foo
foo.cc: In function ‘int main()’:
foo.cc:11: warning: unused variable ‘f’
beachboys++ /tmp> g++ --version
g++ (GCC) 4.1.2 20061115 (prerelease) (Debian 4.1.1-21)
Copyright (C) 2006 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is
NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR
PURPOSE.

Same effect with gcc 3.3 and 3.4. However a

  typedef Foo Quux __attribute__ ((deprecated));

with

  int main() {
	Quux f;

	return 0;
  };

does what I expected:

foo.cc: In function `int main()':
foo.cc:11: warning: `Quux' is deprecated (declared at foo.cc:8)
foo.cc:11: warning: unused variable `Quux f'

Did I understand anything wrong? Or is this a bug/feature? :-)

Please CC me on reply, I'm not subscribed to gcc-help.

Cheers
   Thimo

Re: How do I deprecate a class?

[Ian Lance Taylor]

Thimo.Neubauer@cst.com writes:

> I concluded that
> 
>   class Foo {
>   public:
> 	void  bar(int x);
>   } __attribute__ ((deprecated));
> 
> should do the trick. However
> 
>   int main() {
> 	Foo f;
> 
> 	return 0;
>   };
> 
> only warns about the (obviously) unused variable but nothing else:

Looks like a bug to me.

And it's been filed already: http://gcc.gnu.org/PR16370

Interestingly, I do get a warning for this:

struct Foo { int i; } __attribute__ ((deprecated));
void foo() { struct Foo f; }

It matters whether I use "struct" or not.  Which is bizarre.

Ian