From: Ian Lance Taylor <iant@google.com>
To: Lennyk <lennyk430@gmail.com>
Cc: gcc-help@gcc.gnu.org
Subject: Re: undefined reference to... when using intel inline asm
Date: Mon, 06 Jul 2009 15:07:00 -0000 [thread overview]
Message-ID: <m3hbxpn937.fsf@google.com> (raw)
In-Reply-To: <4A51AA7D.4060809@gmail.com> (Lennyk's message of "Mon\, 06 Jul 2009 10\:40\:45 +0300")
Lennyk <lennyk430@gmail.com> writes:
> According to the guide - the corresponding GCC translation - should
> look like this:
>
> void bswap(int* n)
> {
> asm("movl %0, %%eax" : : "g" (*n));
> asm("bswap %eax");
> asm("movl %%eax, %0" : "=g" (*n));
> }
>
> But, for some reason, the result is not a "bswapped" n.
> Why?
* What does the generated code look like?
* You shouldn't break up the asm statements like that--write one asm
with three assembler statements.
* Let the compiler do the data movement for you; it's good at it.
* If you're going to clobber %eax in an asm, you need to say so
explicitly; that's probably why this code sequence is breaking.
asm("bswap %%eax" : : : "eax");
Anyhow, I would write it like this:
void bswap(int* n)
{
asm("bswap %0" : "=r" (*n) : "0" (*n));
}
Ian
next prev parent reply other threads:[~2009-07-06 15:07 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-07-02 8:04 Lennyk
2009-07-02 19:52 ` Ian Lance Taylor
2009-07-06 7:40 ` Lennyk
2009-07-06 15:07 ` Ian Lance Taylor [this message]
2009-07-07 10:51 ` Lennyk
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