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To: Wei Qin <wqin@EE.Princeton.EDU>
Cc: gcc-help@gcc.gnu.org
Subject: Re: Proper and portable ways using manipulator
References: <Pine.SOL.4.43.0308071808180.5638-100000@ivy.ee.princeton.edu>
From: LLeweLLyn Reese <llewelly@lifesupport.shutdown.com>
Date: Fri, 08 Aug 2003 04:46:00 -0000
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Wei Qin <wqin@EE.Princeton.EDU> writes:

> Hi,
> 	I used some manipulators in the form of
> 
> #include <iostream>
> #include <ios>

Try:
#include <iomanip>

instead. (Note: I don't have 2.96 availible to test.)

> 
> int main () {
> 
> 	std::cout << std::showbase << std::hex << 100 << std::endl;
> }
> 
> 	This compiles fine with g++ 3.x. However, it fails on g++ 2.96
> since it cannot find ios. When I remove ios, it cannot find showbase. Then
> I change std::showbase to std::ios::showbase, but this showbase is not a
> manipulator any more. As a result the program outputs 8064 instead of
> 0x64.
> 	So my question is: Is there any good coding practice to make sure
> that the same code compiles for both and works as intended? Thanks.

Compile every change with both compilers.