Re: c/6547: misleading printf '$' format

["Pierre-Canalsat PETIT" <pierrecanalsat.petit.canalsat@canal-plus.com>]

The following reply was made to PR c/6547; it has been noted by GNATS.

From: "Pierre-Canalsat PETIT" <pierrecanalsat.petit.canalsat@canal-plus.com>
To: jsm28@cam.ac.uk
Cc: gcc-bugs@gcc.gnu.org,
	gcc-gnats@gcc.gnu.org,
	Joseph Myers <jsm28@srcf.ucam.org>,
	peio@blutch.dyndns.org,
	prpetit@canal-plus.com
Subject: Re: c/6547: misleading printf '$' format
Date: Fri, 3 May 2002 16:18:13 +0200

 > You can't mix $ and non-$ formats in one format string; see the Single
 > Unix Specification.  Once a non-$ format is detected, $ operand numbers
 > are no longer checked for.  Note that "%." can only be the start of a
 > non-$ format.
 
 ====(forgot to answer to all...)====
 
 True.. I forgot that, thanks.
 So gcc-3.0 has no misleading warning, good point
 (maybe a more verbose warning should be written..).
 
 Note v2.95.4 still has one :
 
 #include <stdio.h>
 int main(int argc, char *argv[]) {
   printf("%2$.*1$s\n", argc, *argv);
   return 0;
 }
 
 This gives a "warning: unknown conversion type character '1' in format"
 
 ====(Snap)====
 
 There is still a problem it seems on gcc v3.0.4.. :
 
 #include <stdio.h>
 #include <string.h>
 
 int main(int argc, char *argv[]) {
   printf("Usage: %1$s [-n <option 1>] [-m <option 2>]\n"
        "       %3$*2$c [-i <input>] [-o <output>] [-c <nb>] [-t <ms>]\n"
        "       %3$*2$c <file.in> <file.out>\n", *argv, strlen(*argv), ' ');
   return 0;
 }
 
 This returns me a "warning: too few arguments for format".
 But if you remove the second line of the format, it does compile
 without warning...
 
 --
 Pierre PETIT