Re: c++/7181: foo<n>::bar = foo<n-1>::bar + foo<n-2>::bar evaluates to zero at compile time

[Paolo Carlini <pcarlini@unitus.it>]

The following reply was made to PR c++/7181; it has been noted by GNATS.

From: Paolo Carlini <pcarlini@unitus.it>
To: Mark Mitchell <mark@codesourcery.com>
Cc: "gcc-gnats@gcc.gnu.org" <gcc-gnats@gcc.gnu.org>, "gcc-prs@gcc.gnu.org"
 <gcc-prs@gcc.gnu.org>, "dobrynin@bigfoot.com" <dobrynin@bigfoot.com>, "gcc-bugs@gcc.gnu.org"
 <gcc-bugs@gcc.gnu.org>, Nathan Sidwell <nathan@codesourcery.com>
Subject: Re: c++/7181: foo<n>::bar = foo<n-1>::bar + foo<n-2>::bar evaluates
 to zero at compile time
Date: Tue, 02 Jul 2002 22:44:41 +0200

 Mark Mitchell wrote:
 
 > --On Tuesday, July 02, 2002 10:28:13 PM +0200 Paolo Carlini 
 > <pcarlini@unitus.it> wrote:
 >
 >> Hi,
 >>
 >> from a very practical point of view, would be difficult to restore the
 >> behaviour of 2.95.x? Note that Intel and Comeau adopts that "particular"
 >> initialization order and the current "equivalent" one ;-) breaks a whole
 >> body of literature on template metaprogramming...
 >
 >
 > Perhaps.  It may also be that picking one order makes this example work,
 > but some similar example fail.
 
 Thanks for your feedback. This one of yours is an important point, 
 indeed. Anyone attempting to restore the old behaviour should first 
 prove that it's really the "best" one in some non trivial sense. I had 
 always believed it is, but...
 
 Thanks again,
 Paolo.