Re: c++/8285: default arg doesn't work in vector

[VLA <verrola@yahoo.com>]

The following reply was made to PR c++/8285; it has been noted by GNATS.

From: VLA <verrola@yahoo.com>
To: nathan@gcc.gnu.org, gcc-bugs@gcc.gnu.org, gcc-prs@gcc.gnu.org,
  nobody@gcc.gnu.org, gcc-gnats@gcc.gnu.org
Cc:  
Subject: Re: c++/8285: default arg doesn't work in vector
Date: Sat, 19 Oct 2002 08:50:40 -0700 (PDT)

 Thanks nathan, the vector constructor use the copy
 constructor to create the other n-1 objects of the
 vector when called with vector<T>(n) but it created an
 instance for each element for vector<T>(n, v).
 
 i saw one object was created, i just couldn't figure
 out why the rest weren't.  
 
 Thanks, you r the man.  but Nathan, i can't remember
 reading about this in the C++ Programming Language. 
 Is this how it should work?  I know, my class should
 have a copy constructor if it has pointer members,  i
 just didn't think the vector would use it.  
 
 Thanks again.
 
 .v
 --- nathan@gcc.gnu.org wrote:
 > Synopsis: default arg doesn't work in vector
 > 
 > State-Changed-From-To: open->feedback
 > State-Changed-By: nathan
 > State-Changed-When: Sat Oct 19 08:25:13 2002
 > State-Changed-Why:
 >     I suspect coding error. You have no user defined
 > copy constructor, therefore one is synthesized by
 > the compiler. If it is ever invoked, you'll end up
 > deleting the same int twice.
 >     
 >     Please confirm whether that fixes the problem or
 > not.
 > 
 >
 http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=8285
 
 
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