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From: Nathanael Nerode <neroden@twcny.rr.com>
Subject: Re: c++/6030: ...
Reply-To: Nathanael Nerode <neroden@twcny.rr.com>
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The following reply was made to PR c++/6030; it has been noted by GNATS.

>>From neroden@twcny.rr.com  Mon Jan 13 01:03:02 2003
From: Nathanael Nerode <neroden@twcny.rr.com>
To: philippeb@videotron.ca, gcc-gnats@gcc.gnu.org, gcc-bugs@gcc.gnu.org,
   nobody@gcc.gnu.org
Cc:  
Subject: Re: c++/6030: ...
Date: Sat, 11 Jan 2003 18:57:18 -0500

 I'm a little confused by all this, but note that the following seems to work:
 --
 #include <utility>
 #include <iostream>
 
 using namespace std;
 
 template <typename _T, _T _V>
         void foo()
         {
                 cout << __PRETTY_FUNCTION__ << endl;
         }
 
 int a = 0;
 
 int b(void) { cout << __PRETTY_FUNCTION__ << endl; }
 
 typedef int (* blah_fn) (void) ;
 
 int main()
 {
         foo<int, 9>();
         foo<blah_fn, b>();
 }
 --
 
 And so does the following:
 --
 #include <utility>
 #include <iostream>
 
 using namespace std;
 
 template <typename _T, _T _V>
         void foo()
         {
                 cout << __PRETTY_FUNCTION__ << endl;
         }
 
 int a = 0;
 
 int b(void) { cout << __PRETTY_FUNCTION__ << endl; }
 
 int main()
 {
         foo<int, 9>();
         foo<int (*) (void), b>();
 }
 --
 
 This seems like a sufficient workaround for most any purpose.  It also works 
 if you replace the * by &.
 
 And it leaves me wondering about the validity of the original. :-)