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From: "Peter A. Buhr" <pabuhr@plg2.math.uwaterloo.ca> To: nobody@gcc.gnu.org Cc: gcc-prs@gcc.gnu.org, Subject: Re: c++/9881: Incorrect address calculation for static class member Date: Thu, 27 Feb 2003 22:56:00 -0000 [thread overview] Message-ID: <20030227225600.11624.qmail@sources.redhat.com> (raw) The following reply was made to PR c++/9881; it has been noted by GNATS. From: "Peter A. Buhr" <pabuhr@plg2.math.uwaterloo.ca> To: bangerth@ticam.utexas.edu Cc: asharji@uwaterloo.ca, gcc-bugs@gcc.gnu.org, gcc-gnats@gcc.gnu.org Subject: Re: c++/9881: Incorrect address calculation for static class member Date: Thu, 27 Feb 2003 17:51:18 -0500 (EST) > Finally, your suggestion is not even > a work-around, because the original problem occurred in separate compilation > units, so the notion of moving the constructor in this case does not apply. At which point you are out of luck in any case, since the standard does not give any guarantee about the order of initialization in case there are more than one translation units. I think it does. All static variables in all translation units must be initialized before any global constructors in any translation unit. The static initialization is usually done by reading constants from the .data section or by the linker/loader. So if I initialize a static variable in one translation unit, it must be initialized before a constructor is run in any another translation unit. I think you are referring to the order of evaluation of global constructors across translation units, which is undefined. May other language lawyers decide this case, regards Let me change the program slightly and see if this clarifies the situation. #include <iostream> using namespace::std; struct bar { double p; }; // bar struct module { static double *b; static double storage; }; class foo { public: foo() { // the output for both values should be the same cout << &module::storage << " " << module::b << endl; } }; foo f; // print output bar v; double *module::b = &(((bar *)(&v))->p); // LINE X //double *module::b = &(((bar *)(&module::storage))->p); // LINE Y double module::storage = 0.0; int main() { } If you run this with gcc3.3, the output is: @awk[5]% a.out 0x8049a50 0x8049a48 Now comment out LINE X, and uncomment LINE Y and run again getting output: @awk[6]% a.out 0x8049a78 0 Zero (0) is not an acceptable address. BUT, the only different between these 2 lines is the chunk of storage for the object. Notice this has nothing to do with the constructor. One case works and one doesn't. Is this not compelling?
next reply other threads:[~2003-02-27 22:56 UTC|newest] Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top 2003-02-27 22:56 Peter A. Buhr [this message] -- strict thread matches above, loose matches on Subject: below -- 2003-03-02 22:16 Wolfgang Bangerth 2003-02-28 13:56 Peter A. Buhr 2003-02-27 23:16 Wolfgang Bangerth 2003-02-27 22:06 Wolfgang Bangerth 2003-02-27 21:46 Peter A. Buhr 2003-02-27 21:40 bangerth 2003-02-27 18:22 bangerth 2003-02-27 18:06 asharji
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