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Date: Thu, 24 Apr 2003 08:36:00 -0000
From: bartoschek@gmx.de
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Subject: c++/10477: Function call not recognized as template
X-SW-Source: 2003-04/txt/msg01023.txt.bz2
List-Id: <gcc-prs.sourceware.org>


>Number:         10477
>Category:       c++
>Synopsis:       Function call not recognized as template
>Confidential:   no
>Severity:       non-critical
>Priority:       medium
>Responsible:    unassigned
>State:          open
>Class:          rejects-legal
>Submitter-Id:   net
>Arrival-Date:   Thu Apr 24 08:36:01 UTC 2003
>Closed-Date:
>Last-Modified:
>Originator:     bartoschek@gmx.de
>Release:        3.2.3
>Organization:
>Environment:
RedHat 9 and Suse Linux 8.2
>Description:
The attached code does not compile. And gives the error

error.C: In member function `void B::f(int)':
error.C:15: parse error before `>' token

The fist < is recognized as operator< and not as the beginning of template arguments.

If you delete Line 11:
class C {};

the code compiles fine. Class C should not affect in any way the behaviour of void B::f(int).

If you delete Class A and use Class C as a template argument:


void B::f(int a)
{
   f<C>();
}

it still does not compile. (class C has to be defined between class B and void B::f(int a))
>How-To-Repeat:
g++ -c error.C
>Fix:

>Release-Note:
>Audit-Trail:
>Unformatted:
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Content-Transfer-Encoding: base64
Content-Disposition: attachment; filename="error.C"

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