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Date: Mon, 05 May 2003 01:14:00 -0000
Message-ID: <20030505011402.20805.qmail@sources.redhat.com>
To: gcc-bugs@gcc.gnu.org, gcc-prs@gcc.gnu.org, nobody@gcc.gnu.org,
  serge.bogdanov@intel.com
From: giovannibajo@libero.it
Reply-To: giovannibajo@libero.it, gcc-bugs@gcc.gnu.org, gcc-prs@gcc.gnu.org,
  nobody@gcc.gnu.org, serge.bogdanov@intel.com, gcc-gnats@gcc.gnu.org
Subject: Re: c++/4337: [2003-01-01]c++ ignores cast operator
X-SW-Source: 2003-05/txt/msg00259.txt.bz2
List-Id: <gcc-prs.sourceware.org>

Synopsis: [2003-01-01]c++ ignores cast operator

State-Changed-From-To: analyzed->closed
State-Changed-By: bajo
State-Changed-When: Mon May  5 01:14:02 2003
State-Changed-Why:
    Not a bug. "a1 = (A1)a2" is a type conversion in cast 
    notation (§5.4). "a1 = const_cast<A1>(a2)" is 
    ill-formed, but "a1 = static_cast<A1>(a2)" is well-formed,
    because "a1 = A1(a2)" is well-formed (this is the exact
    condition specified by §5.2.9p2). Thus, for §5.4p5, the
    cast notation is equivalent to the static_cast notation.
    The static_cast notation is then equivalent to 
    "a1 = A1(a2)", which upcasts a2 to const A& implicitally,
    and then invokes A1(const A&). 
    G++ behaves exactly as the standard prescribes, and all
    the other compilers I have agree.
    If you need to force the use of the custom conversion 
    operator, you can still do it using the syntax
    "a1 = a2.operator A1()".

http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=4337